I believe the answer is A) Less work in less time.
Answer:
The rate of change of the distance between the helicopter and yourself (in ft/s) after 5 s is
ft/ sec
Explanation:
Given:
h(t) = 25 ft/sec
x(t) = 10 ft/ sec
h(5) = 25 ft/sec . 5 = 125 ft
x(5) = 10 ft/sec . 5 = 50 ft
Now we can calculate the distance between the person and the helicopter by using the Pythagorean theorem
![D(t) = \sqrt{h^2 + x^2}](https://tex.z-dn.net/?f=D%28t%29%20%3D%20%5Csqrt%7Bh%5E2%20%2B%20x%5E2%7D)
Lets find the derivative of distance with respect to time
![\frac{dD}{dt} (t) = \frac{2h \cdot \frac{dh}{dt} +2x \cdot\frac{dx}{dt}} {2\sqrt{h^2 + x^2}}](https://tex.z-dn.net/?f=%5Cfrac%7BdD%7D%7Bdt%7D%20%28t%29%20%20%3D%20%5Cfrac%7B2h%20%5Ccdot%20%5Cfrac%7Bdh%7D%7Bdt%7D%20%2B2x%20%5Ccdot%5Cfrac%7Bdx%7D%7Bdt%7D%7D%20%7B2%5Csqrt%7Bh%5E2%20%2B%20x%5E2%7D%7D)
Substituting the values of h(t) and x(t) and simplifying we get,
![\frac{dD}{dt}(t) = \frac{50t \cdot \frac{dh}{dt} + 20 \cdot \frac{dx}dt}{2\sqrt{625\cdot t^2 + 100 \cdot t^2}}](https://tex.z-dn.net/?f=%5Cfrac%7BdD%7D%7Bdt%7D%28t%29%20%3D%20%5Cfrac%7B50t%20%5Ccdot%20%5Cfrac%7Bdh%7D%7Bdt%7D%20%2B%2020%20%5Ccdot%20%5Cfrac%7Bdx%7Ddt%7D%7B2%5Csqrt%7B625%5Ccdot%20t%5E2%20%2B%20100%20%5Ccdot%20t%5E2%7D%7D)
![\frac{dh}{dt} = 25ft/sec](https://tex.z-dn.net/?f=%5Cfrac%7Bdh%7D%7Bdt%7D%20%3D%2025ft%2Fsec)
![\frac{dx}{dt} = 10 ft/sec](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%7D%7Bdt%7D%20%3D%2010%20ft%2Fsec)
=
=
ft / sec
Answer:
An object which moves in the positive direction has a positive velocity. If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion (in this case, a negative acceleration).
Explanation:
Answer with Explanation:
We are given that
![D_1=0.15mGy](https://tex.z-dn.net/?f=D_1%3D0.15mGy)
![D_2=0.22mGy](https://tex.z-dn.net/?f=D_2%3D0.22mGy)
![Q_1=6](https://tex.z-dn.net/?f=Q_1%3D6)
![Q_2=10](https://tex.z-dn.net/?f=Q_2%3D10)
a.We have to find the total dose
Total dose=![D=D_1+D_2](https://tex.z-dn.net/?f=D%3DD_1%2BD_2)
Using the formula then, we get
![D=0.15+0.22](https://tex.z-dn.net/?f=D%3D0.15%2B0.22)
![D=0.37mGy](https://tex.z-dn.net/?f=D%3D0.37mGy)
b.We have to find the total dose equivalent
Total dose equivalent=H=![D_1Q_1+D_2Q_2](https://tex.z-dn.net/?f=D_1Q_1%2BD_2Q_2)
Using the formula
![H=0.15(6)+0.22(10)](https://tex.z-dn.net/?f=H%3D0.15%286%29%2B0.22%2810%29)
H=3.1mSv
It is basically shielding a magnetic field. This can be done with rubber or any other material that is thick. Normally small magnets already block the shield.