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4 years ago

Please help me with this question someone

Physics

2 answers:

Gekata [30.6K]4 years ago

8 0

From the answers provided, I believe the possible answer would be the last option, silicon, oxygen, and one or more metals. Here's my reasoning: the most abundant mineral group found in the Earth's crust is the silicate group. The silicate materials contain both oxygen and silicon. Silicates are the most common minerals in the rock-formation process, and it has, in fact, been estimated that they make up 75 to 90 percent of the Earth's crust. From this piece of evidence, I can guess that the answer will possibly be D, silicon, oxygen, and one or more metals.
It should also be noted that the additional elements that combine with the silicon-oxygen tetrahedron are involved with the other elements commonly found in the Earth's crust and mantle. They are aluminum, calcium, iron, magnesium, potassium and sodium.

Marianna [84]4 years ago

5 0

The last option, silicon, oxygen, and one or more metals

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Commercials for a toy bouncy ball advertise that it will bounce to a height that is greater than the

storchak [24]

Answer:

because energy will be lost due to friction, sound, and heat (arguably similar to friction) and ENERGY MUST STAY THE SAME so it is IMPOSSIBLE for the ball to bounce higher than when dropped!

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4 years ago

Which of the following is a device designed to open an overloaded circuit and prevent overheating?

spin [16.1K]

Circuit breaker is a device that is designed to open an overloaded circuit and prevent overheating. The correct option in regards to the given question is option "a". The main purpose of the circuit breaker is to disconnect the defective switch from the circuit as soon as any problem arises. This helps in preventing any kind of major accident. Overheating can result in a big accident and the circuit breaker is the device that senses the overheating and disconnects the switch before any major incident. It is an automated system that acts as a protective devise.

4 0

3 years ago

check the file.........................................................................................................

White raven [17]

What is meant by the number of complete oscillation made by an oscillating body in 10 seconds is 500 complete oscillations is that the frequency of the oscillating body is 50Hz

<h3>What is frequency?</h3>

Frequency of an oscillating body can be defined as the number of complete oscillations per unit time

Frequency is measured in hertz (Hz).

Also, the frequency of 1Hz is one oscillation per second.

frequency = number of oscillations/ time taken

frequency = 500/10 = 50 Hz

Thus, what is meant by the number of complete oscillation made by an oscillating body in 10 seconds is 500 complete oscillations is that the frequency of the oscillating body is 50Hz

Learn more about frequency here:

brainly.com/question/1199084

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6 0

2 years ago

In the qualifying round of the 50-yd freestyle in the sectional swimming championship, Dugan got an early lead by finishing the

Nata [24]

Answer:

v = 0

Explanation:

Given that,

Total distance is 50 yards

Dugan got an early lead by finishing the first 25.00 yd in 10.01 seconds

Dugan finished the return leg (25.00 yd distance) in 10.22 seconds.

We need to find Dugan's average velocity for the entire race. As he returns at the initial position. As a result, the net displacement is equal to 0. So,

Average velocity = net displacement/time

v = 0

Hence, his average velocity for the entire race is 0.

6 0

4 years ago

Find the electric field at a point midway between two charges of +40.0 x 10^-9 c and.+60.0 x 10^-9 c

PIT_PIT [208]

Missing part in the text: "...the charges are <span>separated by a distance of 30.0 cm."
</span>
Solution:
The point midway between the two charges is located 15.0 cm from one charge and 15.0 from the other charge. The electric field generated by each of the charges is
$E=k_e \frac{q}{r^2}$
where
ke is the Coulomb's constant
Q is the value of the charge
r is the distance of the point at which we calculate the field from the charge (so, in this problem, r=15.0 cm=0.15 m).

Let's calculate the electric field generated by the first charge:
$E_1 = (8.99 \cdot 10^9 Nm^2 C^{-2} ) \frac{+40.0 \cdot 10^{-9} C}{(0.15 m)^2}=1.6 \cdot 10^4 N/C$

While the electric field generated by the second charge is
$E_2 = (8.99 \cdot 10^9 N m^2 C^{-2} ) \frac{+60.0 \cdot 10^{-9} C}{(0.15 m)^2}=2.4 \cdot 10^4 N/C$

Both charges are positive, this means that both electric fields are directed toward the charge. Therefore, at the point midway between the two charges the two electric fields have opposite direction, so the total electric field at that point is given by the difference between the two fields:
$E=E_2 - E_1 = 2.4 \cdot 10^4 N/C - 1.6 \cdot 10^4 N/C = 8000 N/C$

4 0

3 years ago