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g100num [7]
3 years ago
10

The air in a balloon is heated up. Give two effects this has on the air particles.

Chemistry
1 answer:
Lisa [10]3 years ago
4 0
Density and mass increases
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PLEASE help!!
Alina [70]

Answer:

<h3>KBr + I- ---------> KI + Br-</h3>

Explanation:

Single Displacement reaction is a chemical Reaction in which one element in the salt is replaced with another element

for example,

A-B + C -------> A-C + B

electropositive replaces only electropositive elements from compound. same is true for electronegative element

in first reaction I being electro negative replaces Br from KBr so this is a single displacement reaction

5 0
3 years ago
How many molecules are in 100 g of C6H120,?*​
Grace [21]

Answer:

3.37 × 10²³ molecules

Explanation:

Given data:

Mass of C₆H₁₂O₆ = 100 g

Number of molecules = ?

Solution:

Number of moles of C₆H₁₂O₆:

Number of moles = mass/molar mass

Number of moles = 100 g/ 180.16 g/mol

Number of moles = 0.56 mol

Number of molecules:

1 mole contain 6.022 × 10²³ molecules

0.56 mol × 6.022 × 10²³ molecules /1 mol

3.37 × 10²³ molecules

6 0
3 years ago
What is the orbital or electronic geometry of a molecule with 0 nonbonding electron pairs and 2 bonding electron pairs?
disa [49]
Linear is the answer
3 0
3 years ago
What must take place for copper metal to be oxidized?
Oxana [17]
 <span>The copper would go under oxidation since it will be losing two electrons. Copper starts out with an oxidation number of zero, but in order to balance the compound of CuO with the Oxygen having an oxidation number of -2, a positive 2 is required</span>
6 0
3 years ago
Calculate the amount of HCl in grams required to react with 3.75 g of CaCO3 according to the following reaction: CaCO3(s) + 2 HC
wolverine [178]

Answer:

The correct answer is 2.75 grams of HCl.

Explanation:

The given balanced equation is:  

CaCO₃ (s) + 2HCl (aq) ⇒ CaCl₂ (aq) + H₂O (l) + CO₂ (g)

Based on the given information, one mole of calcium carbonate is reacting with two moles of HCl. The molecular mass of HCl is 36.5 grams, thus, the mass of 2 moles of HCl will be, 36.5 × 2 = 73 grams

The molecular mass of CaCO₃ is 100 gram per mole, that is, the mass of 1 mole of CaCO₃ is 100 grams, therefore, the mass of HCl required for reacting with 3.75 grams of CaCO₃ will be,  

= 3.75 × 2 × 36.5 / 100 = 2.74 grams of HCl.  

8 0
3 years ago
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