Answer:
p and d orbitals
Explanation:
A π bond forms when two orbitals overlap side-on.
The most common types are formed by the overlap of p orbitals (Fig. 1).
However, d orbitals can also overlap sideways with each other to form dπ-dπ bonds and with p orbitals to form dπ-pπ bonds (Fig.2).
It is either mass or volume
.energy mechanical needs it Answer:
Yes.
Explanation:
The conversion of 2 - butanol to 2 - nitrobutane involves conversion of 2 butanol to 2 - bromobutane and subsequently to 2 - nitrobutane.
In order to convert 2 - butanol to 2 - nitrobutane, an SN2 reaction is first carried out in which 2 - butanol is converted to 2 - bromobutane. This reaction proceeds with inversion of configuration at the chiral carbon as expected.
This product is subsequently reacted with silver nitrite in ethanol to yield 2 - nitrobutane along side silver bromide. Some alkyl nitrite is also produced as a by product. The components of the mixture are separated by fractional distillation. The scheme of the reaction is shown in the image attached to this answer. This reaction is only applied to primary and secondary alkyl halides.
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Answer:
11.72 grams
Explanation:
Let the equilibrium concentration of BrCl be y
Initial concentration of Br2 = number of moles ÷ volume = (0.979×1000/160) ÷ 199 = 0.031 M
Initial concentration of Cl2 = (1.075×1000/71) ÷ 199 = 0.076 M
From the equation of reaction
1 mole of Br2 reacted with 1 mole of Cl2 to form 2 moles of BrCl
Therefore, equilibrium concentration of Br2 = (0.031 - 0.5y) M while that of Cl2 = (0.076 - 0.5y) M
Kp = [BrCl]^2/[Br2][Cl2]
1.1×10^-4 = y^2/(0.031 - 0.5y)(0.076 - 0.5y)
y^2/0.002356-0.0535y+0.25y^2 = 0.00011
y^2/0.00011 = 0.002356-0.0536y+0.25y^2
9090.9y^2-0.25y^2+0.0536y-0.002356 = 0
9090.65y^2+0.0535y-0.002356 = 0
The value of y must be positive and is obtained using the quadratic formula
y = [-0.0535 + sqrt(0.0535^2 - 4×9090.65×-0.002356)] ÷ 2(9090.65) = 9.2025/18181.3 = 0.00051 M
Mass of BrCl = concentration×volume×MW = 0.00051×199×115.5 = 11.72 grams