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kozerog [31]
3 years ago
8

How many surrounding electrons

Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

A

Explanation:

Chlorine has one valence electron

Hence one chlorine atom reacts with 2 atoms of lithium

And also reacts with 3 atoms of boron

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Explanation:

Burning fossil fuels, changing land use, and using limestone to make concrete all transfer significant quantities of carbon into the atmosphere

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What type of air masses might make up the cold air mass in a cold front
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continental polar air masses

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forms over Canada, move down from North Pole, bring bitterly cold and dry air to the northern United States during the winter.

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How many milliliters of a stock solution of 12.1 M HNO3 would be needed to prepare 0.500 L of 0.500 M HNO3
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2 years ago
Calculate the pH of 1.00 L of a buffer that contains 0.105 M HNO2 and 0.170 M NaNO2. What is the pH of the same buffer after the
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Answer:

1.- pH =3.61

2.-pH =3.53

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pH = pKa + log [A⁻]/[HA]

where [A⁻] is the conjugate base anion concentration ( [NO₂⁻]), [HA] is the weak acid concentration,[HNO₂].

In the second part, our strategy has to take into account that some of the weak base NO₂⁻ will be consumed by reaction with the very strong acid HCl. Thus, first we will calculate the new concentrations, and then find the new pH similar to the first part.

First Part

pH  = 3.40+ log {0.170 /0.105}

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Second Part

# mol HCl = ( 0.001 L ) x 12.0 mol / L = 0.012

# mol NaNO₂ reacted = 0.012 mol ( 1: 1 reaction)

# mol NaNO₂ initial = 0.170 mol/L x 1 L = 0.170 mol

# mol NaNO₂ remaining = (0.170 - 0.012) mol  = 0.158

# mol HNO₂ produced = 0.012 mol

# mol HNO₂ initial = 0.105

# new mol HNO₂ = (0.105 + 0.012) mol = 0.117 mol

Now we are ready to use the Henderson-Hasselbach with the new ration. Notice that we dont have to calculate the concentration (M) since we are using a ratio.

pH = 3.40 + log {0.158/.0117}

pH = 3.53

Notice there is little variation in the pH of the buffer. That is the usefulness of buffers.

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