Answer:
1.2 M.
Explanation:
<em>Molarity is the no. of moles of solute in a 1.0 L of the solution.</em>
M = n/V.
<em>M = (mass/molar mass)solute x (1000/V of the solution).</em>
mass of NaOH = 120.0 g.
molar mass of NaOH = 40.0 g/mol.
V of the solution = 2.5 L = 2500.0 mL.
<em>∴ M = (mass/molar mass)solute x (1000/V of the solution)</em> = (120.0 g / 40.0 g/mol) x (1000 / 2500.0 mL) = <em>1.2 M.</em>
Answer: The enthalpy of formation of 
is -396 kJ/mol
Explanation:
Calculating the enthalpy of formation of
The chemical equation for the combustion of propane follows:
The equation for the enthalpy change of the above reaction is:
![\Delta H^o_{rxn}=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta H^o_f_{(SO_2(g))})+(1\times \Delta H^o_f_{(O_2(g))})]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%282%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28SO_3%28g%29%29%7D%29%5D-%5B%282%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28SO_2%28g%29%29%7D%29%2B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28O_2%28g%29%29%7D%29%5D)
We are given:
Putting values in above equation, we get:
![-198=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta -297)+(1\times (0))]\\\\\Delta H^o_f_{(SO_3(g))}=-396kJ/mol](https://tex.z-dn.net/?f=-198%3D%5B%282%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28SO_3%28g%29%29%7D%29%5D-%5B%282%5Ctimes%20%5CDelta%20-297%29%2B%281%5Ctimes%20%280%29%29%5D%5C%5C%5C%5C%5CDelta%20H%5Eo_f_%7B%28SO_3%28g%29%29%7D%3D-396kJ%2Fmol)
The enthalpy of formation of is -396 kJ/mol
In the summer, in the southern hemisphere. when it is summer is the northern, it is winter in the southern. all year along, the most sun hits the equator, but when it is winter in the northern hemisphere (thats when Alaska goes dark because of no sun) there is summer in the southern Hemusphere such as continents like south america, india, africa, and places like that :)
Hey there!:
Detailed solution is shown below ask if any doubt :
