Vf = Vi + at
Vf = 0 + 5.4•28
= 151.2m/s..
not sure if its right
For the answer to the question above,
Ricardo goes a distance (magnitude) of 27, in a direction of 60 degrees W of N
<span>Jane goes a magnitude of 16 in a direction 30 degrees S of W </span>
<span>How I would solve this is to imagine that the started at (0,0) </span>
<span>And their walking represents vectors. </span>
<span>Ricardo: </span>
<span>X-coordinate = -27sin60 = 27sqrt(3)/2 = 23.383 </span>
<span>Y-coordinate = 27cos60 = 27/2 = 13.5 </span>
<span>So, after he walks, he is at point (-23.383, 13.5) </span>
<span>Jane: </span>
<span>X-coordinate = -16cos(30) = 16sqrt(3)/2 = 13.856 </span>
<span>Y-coordinate = -16sin(30) = 16/2 = 8 </span>
<span>So, after she walks, she is at point (-13.856, -8) </span>
<span>So, you have 2 points. </span>
<span>Use the distance formula to find their distance apart </span>
<span>Sqrt((-23.383+13.856)^2+(13.5+8)^2) = 23.516m </span>
<span>To find the direction, simply find the slope of the two points, and take the arc-tangent. </span>
<span>The slope = -9.527/21.5 = -0.443 </span>
<span>Take the tan^-1 of this, which is -23.899 degrees. </span>
<span>This basically translates to, Ricardo must walk 23.899 degrees E of S </span>
<span>They will be 23.518 m apart </span>
<span>Ricardo must walk 23.899 degrees East of South to get to Jane</span>
The answer is 179J let me know if you need the work