Answer:
Part a)

Part b)

Explanation:
Part a)
As we know that initially the two blocks are connected by a spring and initially stretched by some amount
Since the two blocks are at rest initially so its initial momentum is zero
since there is no external force on this system so final momentum is also zero

now for initial position the speed is zero

now we have

Part b)
now for ratio of kinetic energy we know that the relation between kinetic energy and momentum is given as

now for the ratio of energy we have

since we know that momentum of two blocks are equal in magnitude so we have
now we have

Answer:
The density ρ of metal block is 8.92g/cm³
So from the given density table this corresponds to copper which has density of 8.92(g/mL)
Explanation:
Oh yeah, I got the correct unit update,
Now this problem bothers on the density of substances
We know that the density of a substance is expressed as
Density ρ= mass/ volume
Given data
Mass of metal block m= 62.44g
Volume of metal block v= 7 cm³
Hence we can find the density of the metal block by plugging in our data into the expression for density
ρ of metal block = 62.44/7
ρ of metal block = 8.92g/cm³
The block is a copper block
Answer:
Explanation:
The electronic configuration of many ions is that if a closes noble gas to them in a periodic table.
An Anion is a ion that has gained one or more electron, acquiring a negative charge.
A Cation is a ion that has lost one or more electron, gaining a positive charge.