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3 years ago

What can you conclude about the direction of motion of the object after the application of the additional force?

1 answer:

5 0

It will move in the direction of applied force following the law of newton that is an object is stationary until an external force is applied then it moves in direction of force

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Help me please!!!

lilavasa [31]

Both planets are similar in shape and have a rocky surface. Not sure about the phases though

7 0

2 years ago

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All organisms have adaptations. The list below describes how different adaptations might affect different species.

VMariaS [17]

I think A, because rodents already live in winter months when little food is available, but I'm not sure.

3 0

3 years ago

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The primary job of a(n) ____ <br> is to increase the power of a modified radio wave.

amm1812

The primary job of a(n) ____

is to increase the power of a modified radio wave.

Answer:

<h2>amplifier</h2>

Explanation:

Hope it helps:)

#CarryOnLearning

4 0

2 years ago

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You throw a bouncy rubber ball and a wet lump of clay, both of mass m, at a wall. Both strike the wall at speed v, but while the

lana [24]

Answer:

<em>The fifth option is the correct answer: mv; 2 mv</em>

Explanation:

<u>Change of Momentum</u>

Assume an object has a momentum p1 and after some interaction it now has a momentum p2, the change of momentum is

$\Delta p=p_2-p_1$

The momentum is computed as

$p=mv$

Where m is the mass of the object and v its speed. Now let's analyze the situation of both the ball and the clay.

The clay has an initial speed v and a mass m, thus its initial momentum is

$p_1=mv$

When it hits the wall, it sticks, thus its final speed is 0 and

$p_2=0$

The change of momentum is

$\Delta p=0-mv=-mv$

The absolute change is mv

Now for the ball, the initial condition is the same as it was for the clay, but the ball hits back at the same speed, thus its final momentum is

$p_2=-mv$

The change of momentum is

$\Delta p=-mv-mv=-2mv$

The absolute change is 2mv

The fifth option is the correct answer: mv; 2 mv

3 0

3 years ago

An airplane flies 20km in a direction 60 degrees north of east, then 30 km straight east, then 10km straight north. How far and

Fed [463]

Answer:

48.4 km, 34.3° north of east

Explanation:

Let's say east is the +x direction and north is the +y direction.

Adding up the x components of the vectors:

x = 20 cos 60 + 30 + 0

x = 40 km

Adding up the y components of the vectors:

y = 20 sin 60 + 0 + 10

y = 27.3 km

The magnitude of the displacement is:

d = √(x² + y²)

d = 48.4 km

The direction is:

θ = atan(y/x)

θ = 34.3° north of east

6 0

3 years ago