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Bess [88]
3 years ago
5

What can you conclude about the direction of motion of the object after the application of the additional force?

Physics
1 answer:
Anna35 [415]3 years ago
5 0

It will move in the direction of applied force following the law of newton that is an object is stationary until an external force is applied then it moves in direction of force

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What does the person in back of the ambulance experience? A) a lower frequency of the siren B) a lower amplitude of the siren C)
hoa [83]

The answer to your question is "A. a lower frequency of the siren.

Because the person in back of the ambulance will hear a lower frequency of the siren. This is because the waves are stretched out. A longer wavelength results in a lower frequency.

5 0
3 years ago
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A nerve impulse travels along a myelinated neuron at 90.1 m/s.<br> What is this speed in mi/h?
algol [13]

Answer:

201.5537 mph

Explanation:

Given the following data;

Speed = 90.1 m/s

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the formula;

Speed = distance/time

To convert this value into miles per hour;

Conversion;

1 meter = 0.000621 mile

90.1 meters = 90.1 * 0.000621 = 0.05595 miles

1 metre per second = 2.237 miles per hour

90.1 meters per seconds = 90.1 * 2.237 = 201.5537 miles per hour

90.1 m/s = 201.5537 mph

7 0
2 years ago
The reflection of a sound wave from a wal is called
WINSTONCH [101]
I think its an echo?
4 0
3 years ago
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Maaf sebelumnya ,bisa minta tolong kerjakan tugas saya? saya harus mengerjakan tugas Fisika yang lain . tolong bantu 4 nomer saj
AlladinOne [14]
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8 0
3 years ago
A proton moving in the positive x direction with a speed of 9.9 105 m/s experiences zero magnetic force. When it moves in the po
Alex

Answer:

The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction

Explanation:

In order to calculate the magnitude and direction of the magnetic field, you take into account the following equation for the magnetic force on the proton:

\vec{F_B}=q\vec{v}\ X\ \vec{B}       (1)

v: speed of the proton = 9.9*10^5 m/s

q: charge of the proton = 1.6*10^-19C

B: magnetic field = ?

FB: magnetic force on the proton = 1.6*10^-13N

When the proton travels in the positive y direction (^j), you have that the proton experiences a force in the positive z direction (+^k). To obtain this direction of the magnetic force on the proton, it is necessary that the magnetic field points in the negative x direction, in fact, you have:

^j X (-^i) = -(-^k)=^k

To obtain the magnitude of the magnetic field you use:

F_B=qvBsin90\°=qvB\\\\B=\frac{F_B}{qv}=\frac{1.6*10^{-13}N}{(1.6*10^{-19}C)(9.9*10^5m/s)}\\\\B=1.01T

The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction

8 0
3 years ago
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