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MA_775_DIABLO [31]
3 years ago
13

A sled of mass m is given a kick on a frozen pond. The kick imparts to it an initial speed of 2.20 m/s. The coefficient of kinet

ic friction between sled and ice is 0.115. Use energy considerations to find the distance the sled moves before it stops. m
Physics
1 answer:
Makovka662 [10]3 years ago
3 0

Answer:

2.15 m

Explanation:

u = 2.2 m/s, v = 0, uk = 0.115

a = uk x g = 0.115 x 9.8 = 1.127 m/s^2

Let s be the distance traveled before stopping.

v^2 = u^2 - 2 a s

0 = 2.2^2 - 2 x 1.127 x s

s = 2.15 m

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A bike rider approaches a hill with a speed of 8.5 m/s. The total mass of the bike rider is 91kg. What is the kinetic energy of
Anestetic [448]

a) The kinetic energy (KE) of an object is expressed as the product of half of the mass (m) of the object and the square of its velocity (v²):

KE = \frac{1}{2}m* v^{2}

It is given:

v = 8.5 m/s

m = 91 kg

So:

KE= \frac{1}{2}*91*8.5^{2} =3,287.4J


b) We can calculate height by using the formula for potential energy (PE):
PE = m*g*h

In this case, h is eight, and PE is the same as KE:
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m = 91 kg

g = 9.81 m/s² - gravitational acceleration

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3,287.4= 91 * 9.81 * h

⇒ h = 3,287.4/(91*9.81) = 3,287.4/892.7 = 3.7 m

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3 years ago
A certain car can accelerate from 0 to 60 mph in 7.9 s. What is the car's average acceleration in mph/s?
Anna007 [38]

Answer:

<em>a = 7.6\ mph/s</em>

Explanation:

<u>Motion With Constant Acceleration </u>

It's a type of motion in which the velocity of an object changes uniformly in time.

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v_f=v_o+at

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t    = time

Solving the equation [for a:

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\displaystyle a=\frac{60 \ mph-0}{7.9}

a = 7.6\ mph/s

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Answer

given,

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thickness of film= 10⁻⁴ cm

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b) phase difference is equal to

Reflection from the first surface has a 180° (½λ) phase change.

There is no phase change for the 2nd surface reflection and there is no phase difference for the 2nd wave having traveled an exact whole number of waves.

net phase difference = 180^0\times \dfrac{3}{2}

                                   = 270°

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