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ivanzaharov [21]
2 years ago
11

Light is incident on an air-water interface at an angle of 30 degree to the normal. What angle does the refracted ray make with

the normal?a.25 degb.19 degc 90 degd.22 deg
Physics
1 answer:
Vikentia [17]2 years ago
6 0

Answer:

22 degree

Explanation:

Angle of incidence, i = 30 degree

the refractive index of water with respect to air is 4/3.

As the ray of light travels from rarer medium to denser medium, that mean air to water, the refraction takes place.

According to Snell's law,

Refractive index of water with respect to air = Sin i / Sin r

Where, r be the angle of refraction

4 / 3 = Sin 30 / Sin r

0.75 = 2 Sin r

Sin r = 0.375

r = 22 degree

Thus, the angle of refraction is 22 degree.

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Anon25 [30]
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3 0
3 years ago
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lys-0071 [83]

Answer:

50%

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8 0
2 years ago
Which formulas have been correctly rearranged to solve for radius? Check all that apply. r = GM central/v^2 r =fcm/v^2 r =ac/v^2
jek_recluse [69]

The orbital radius is: r=\frac{GM}{v^2}

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\frac{GMm}{r^2}=m\frac{v^2}{r}

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Re-arranging the equation, we find:

\frac{GM}{r}=v^2\\r=\frac{GM}{v^2}

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

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7 0
3 years ago
Read 2 more answers
Justin Bieber is thrown horizontally at 10.0 m/s from the top of a cliff 122.5 m high.
sveticcg [70]

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Divide each side by (4.9 m/s²):   (122.5 m / 4.9 m/s²)  =  time²

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Take the square root of each side:    5.0 seconds


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7 0
3 years ago
Read 2 more answers
Which is the main purpose of an experimental conclusion?
Reptile [31]

Answer:

the Answer is B

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8 0
3 years ago
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