1. You get to build cool things for places like nasa.
2. You get paid very well
Hope this helps
Answer:
Explanation:
kindly check he attached file below
Answer:
Rate of heat loss per unit length of pipe, q' = 767.01 W/m
Explanation:
Let q' be the Rate of heat loss per unit length
Let q be the Rate of heat loss
q' = q/L
Where L is the length of the pipe
Diameter, D= 0.6m
The rate of heat loss q is given by the formula: q = Sk(T₂ - T₁)
Where k is the thermal conductivity of the concrete at 300 K
k = 1.4 Wb/m-K (at 300K)
And S is the shape factor given by the formula:
S = 2πL/ ln(1.08w/D)
S = (2π*L) / ln(1.08*1.75/0.6))
S = (2π*L) / 1.147
S = 5.48 L
q = 5.48L*1.4(400-300)
q = 767.01 L
q' = q/L
q' = 767.01L/L
q' = 767.01 W/m
In an alternating current (AC) circuit the two poles alternate between negative and positive and the direction of the current (electron flow) reverses periodically.
