Solution :
![$P_1 = 120 \ psia$](https://tex.z-dn.net/?f=%24P_1%20%3D%20120%20%5C%20psia%24)
![$P_2 = 20 \ psia$](https://tex.z-dn.net/?f=%24P_2%20%3D%2020%20%5C%20psia%24)
Using the data table for refrigerant-134a at P = 120 psia
![$h_1=h_f=40.8365 \ Btu/lbm$](https://tex.z-dn.net/?f=%24h_1%3Dh_f%3D40.8365%20%5C%20Btu%2Flbm%24)
![$u_1=u_f=40.5485 \ Btu/lbm$](https://tex.z-dn.net/?f=%24u_1%3Du_f%3D40.5485%20%5C%20Btu%2Flbm%24)
![$T_{sat}=87.745^\circ F$](https://tex.z-dn.net/?f=%24T_%7Bsat%7D%3D87.745%5E%5Ccirc%20%20F%24)
∴ ![$h_2=h_1=40.8365 \ Btu/lbm$](https://tex.z-dn.net/?f=%24h_2%3Dh_1%3D40.8365%20%5C%20Btu%2Flbm%24)
For pressure, P = 20 psia
![$h_{2f} = 11.445 \ Btu/lbm$](https://tex.z-dn.net/?f=%24h_%7B2f%7D%20%3D%2011.445%20%5C%20Btu%2Flbm%24)
![$h_{2g} = 102.73 \ Btu/lbm$](https://tex.z-dn.net/?f=%24h_%7B2g%7D%20%3D%20102.73%20%5C%20Btu%2Flbm%24)
![$u_{2f} = 11.401 \ Btu/lbm$](https://tex.z-dn.net/?f=%24u_%7B2f%7D%20%3D%2011.401%20%5C%20Btu%2Flbm%24)
![$u_{2g} = 94.3 \ Btu/lbm$](https://tex.z-dn.net/?f=%24u_%7B2g%7D%20%3D%2094.3%20%5C%20Btu%2Flbm%24)
![$T_2=T_{sat}=-2.43^\circ F$](https://tex.z-dn.net/?f=%24T_2%3DT_%7Bsat%7D%3D-2.43%5E%5Ccirc%20%20F%24)
Change in temperature, ![$\Delta T = T_2-T_1$](https://tex.z-dn.net/?f=%24%5CDelta%20T%20%3D%20T_2-T_1%24)
![$\Delta T = -2.43-87.745$](https://tex.z-dn.net/?f=%24%5CDelta%20T%20%3D%20-2.43-87.745%24)
![$\Delta T=-90.175^\circ F$](https://tex.z-dn.net/?f=%24%5CDelta%20T%3D-90.175%5E%5Ccirc%20%20F%24)
Now we find the quality,
![$h_2=h_f+x_2(h_g-h_f)$](https://tex.z-dn.net/?f=%24h_2%3Dh_f%2Bx_2%28h_g-h_f%29%24)
![$40.8365=11.445+x_2(91.282)$](https://tex.z-dn.net/?f=%2440.8365%3D11.445%2Bx_2%2891.282%29%24)
![$x_2=0.32198$](https://tex.z-dn.net/?f=%24x_2%3D0.32198%24)
The final energy,
![$u_2=u_f+x_2.u_{fg}$](https://tex.z-dn.net/?f=%24u_2%3Du_f%2Bx_2.u_%7Bfg%7D%24)
![$=11.401+0.32198(82.898)$](https://tex.z-dn.net/?f=%24%3D11.401%2B0.32198%2882.898%29%24)
![$=38.09297 \ Btu/lbm$](https://tex.z-dn.net/?f=%24%3D38.09297%20%5C%20Btu%2Flbm%24)
Change in internal energy
![$\Delta u= u_2-u_1$](https://tex.z-dn.net/?f=%24%5CDelta%20u%3D%20u_2-u_1%24)
= 38.09297-40.5485
= -2.4556
That due to the specific tasks that needs to be accomplished by each program to make an all encompassing program would be inefficient and full of bugs
Answer:
Hook's law holds good up to. A elastic limit. B. plastic limit. C.yield point. D.Breaking point