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Sidana [21]
3 years ago
14

An aircraft increases its speed by 2% in straight and level flight. If the total lift remains constant determine the revised CL

as a percentage of its original value to three significant figure
Engineering
1 answer:
damaskus [11]3 years ago
7 0

Answer:

96.1%

Explanation:

We know that lift force

F_L=\dfrac{1}{2}C_L\rho AV^2

                                                                    ------------(1)

Where C_L is the lift force coefficient .

          ρ is the density of fluid.

         A is the area.

        V is the velocity.

Now when speed is increased by 2 % and all other parameter remains constant except C_L .

Let;s take new value of lift force coefficient is C_L' .

F_L=\dfrac{1}{2}C_L'\rho A(1.02V)^2

                                                                         -----------(2)

Now from equation 1 and 2

C_L\times V^2=C_L'\times1.0404 V^2

⇒C_L'=0.961C_L

So we can say that revised value of  lift force coefficient is 96.1% of original value.

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The component of a fluid system where a fluid is stored, but not under pressure, is called a container.
forsale [732]

Answer:

The answer is true

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Explanation:

6 0
3 years ago
A gas has an initial volume o.25m^3, and absolute pressure 100kPa. Its initial temperature is 290k. The gas is compressed into a
dezoksy [38]

Answer:

<h2>698.3Kpa</h2>

Explanation:

Step one:

given data

V1=0.25m^3

T1=290k

P1=100kPa

V2=0.5m^2

T2=405k

P2=? final pressure

Step two:

The combined gas equation is given as

P1V1/T1=P2V2/T2

Substituting we have

(100*0.25)/290=P2*0.05/405

25/290=0.5P2/405

0.086=0.05P2/405

cross multiply

0.086*405=0.05P2

34.9=0.05P2

divide both sides by 0.05

P2=34.9/0.05

P2=698.3Kpa

<u>Therefore the new pressure is 698.3Kpa when the gas is compressed</u>

5 0
3 years ago
Twenty-five wooden beams were ordered or a construction project. The sample mean and he sample standard deviation were measured
aksik [14]

Answer:

Correct option: B. 90%

Explanation:

The confidence interval is given by:

CI = [\bar{x} - z\sigma_{\bar{x}} , \bar{x}+z\sigma_{\bar{x}} ]

If \bar{x} is 190, we can find the value of z\sigma_{\bar{x}}:

\bar{x} - z\sigma_{\bar{x}}  = 188.29

190 - z\sigma_{\bar{x}}  = 188.29

z\sigma_{\bar{x}}  = 1.71

Now we need to find the value of \sigma_{\bar{x}}:

\sigma_{\bar{x}} = s / \sqrt{n}

\sigma_{\bar{x}} = 5/ \sqrt{25}

\sigma_{\bar{x}} = 1

So the value of z is 1.71.

Looking at the z-table, the z value that gives a z-score of 1.71 is 0.0436

This value will occur in both sides of the normal curve, so the confidence level is:

CI = 1 - 2*0.0436 = 0.9128 = 91.28\%

The nearest CI in the options is 90%, so the correct option is B.

4 0
4 years ago
What does WCS stand for? A. Western CAD System B. Worldwide Coordinate Sectors C. World Coordinate System D. Wrong CAD Settings
Ray Of Light [21]

Answer:

The correct answer is C. World Coordinate System

Explanation:

The World Coordinate System has to do with that coordinate system which is fixed in the activities of the CADing. There is a default system in which we can refer to them as soon as we want to manipulate the objects and add new elements.

7 0
3 years ago
Nearlyof all serious occupational injuries and illnesses stem from overexertion of repetitive motion.
Ostrovityanka [42]

Answer:

a) 1/2

Explanation:

Overexertion accounted for more than  half of all events that resulted in a disabling condition.

Furthermore, 30% of all overexertion cases were reported in the services industry, on the other hand, 25% of injuries resulting from contact with objects and  equipment occurred in the manufacturing industry.

The above piece of information is taken from the bureau of labor statistics, Survey of Occupational Injuries and Illnesses

"LOST-WORKTIME INJURIES AND ILLNESSES: CHARACTERISTICS  AND RESULTING DAYS AWAY FROM WORK, 2002"

8 0
4 years ago
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