Answer:
(a) Friction force = 50 N
(b) Work done by friction = 300 j
(c) Net work done = 0 j
Explanation:
We have given that the box is pulled by 6 meter so d = 6 m
Force applied on the box F = 60 N
We have have given that velocity is constant so acceleration will be zero
So to applied force will be utilized in balancing the friction force
So friction force 
Work done by friction force 
Work done by applied force 
So net work done = 300-300 = 0 j
Answer: 5.5km
Explanation:
Atmospheric pressure will be 500 mb (that is half of the total 1000mb air pressure).
Pressure decreases with increasing altitude. This is because at At higher altitudes, there are fewer air molecules above a the known or given surface than a similar surface at lower levels.
Pressure decreasing with higher altitudes also means that air pressure decreases rapidly at lowerevels but more slowly at higher levels.
It is also known that more than half of the atmospheric molecules are located below 5.5 km(that is atmospheric pressure decreases within the lowest 5.5 km to about fifty(50) percent( that is 500 millibar).
Answer:
The angular acceleration of the wheel is -6.54 rad/s²
Explanation:
We'll use the equations of motion for this.
w = 2πf
f = 75 rpm = 1.25 rps = 1.25 rev/s
w₀ = initial angular velocity = 2π × 1.25 = 7.85 rad/s
w = final angular velocity = 0 rad/s
t = 1.2 s
α = ?
w = w₀ + αt
0 = 7.85 + 1.2α
α = 7.85/1.2 = - 6.54 rad/s²
Carbon dioxide
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