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loris [4]
3 years ago
9

Mercury (Hg) poisoning is a debilitating disease that is often fatal. In the human body, mercury reacts with essential enzymes l

eading to irreversible inactivity of these enzymes. If the amount of mercury in a polluted lake is 0.4 \muμg Hg/mL, what is the total mass in kilograms of mercury in the lake? (The lake has a surface area of 100 mi2 and an average depth of 20 ft.) (1 mile = 5280 ft; 1 ft = 12 in; 2.54 cm = 1 in) (Use scientific notation)
Chemistry
1 answer:
alisha [4.7K]3 years ago
3 0

Answer:

6 x 10⁵ kg Hg

Explanation:

The mass of mercury in the entire lake is found by multiplying the concentration of the mercury by the volume of the lake.

The volume of the lake is calculated in cubic feet:

V = (SA)x(depth) = (100mi²)(5280ft/mi)² x (20ft) = 5.57568 x 10¹⁰ ft³

Cubic feet are then converted to mL (1cm³=1mL)

(5.57568 x 10¹⁰ ft³) x (12in/ft)³ x (2.54cm/in)³ = 1.578856752 x 10¹⁵ mL

The mass of mercury is then found:

m = CV = (0.4μg/mL)(1g/10⁶μg)(1kg/1000g) x (1.578856752 x 10¹⁵ mL) = 6 x 10⁵ kg Hg

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Energy in the amount of 420 J is added to a 35 g sample of water at a temperature of 10°C. What is the final temperature of the
Vsevolod [243]

The <em>final temperature </em><em>of the</em><em> water, T2</em> = <em>38.57°C</em>

Temperature can be defined as a measure of the degree of hotness or coldness of a physical object (body). Thus, it is measured with a thermometer and its units are degree Celsius (°C), Fahrenheit (°F) and Kelvin (°K).

A calorie refers to the amount of heat required to raise the temperature of a gram of water by one (1) degree Celsius (1°C).

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<u>Given the following data:</u>

  • Quantity of energy = 420J
  • Mass = 35 grams
  • Initial temperature, T1 = 10°C

The specific heat capacity of water is 4.2 J/g°C.

To find the final temperature of the water (T2):

Mathematically, the quantity of energy (heat capacity) is given by the formula;

Q = mcdt

Where;

  • Q represents the heat capacity or quantity of heat.
  • M represents the mass of an object.
  • C represents the specific heat capacity of water.
  • dt represents the change in temperature.

Substituting the values into the formula, we have;

420 = 3.5 \; * \; 4.2 \; * \;  dt

420 = 14.7 \; * \; dt\\\\dt = \frac{420}{14.7}

Change in temperature, dt = 28.57°C

Next, we would solve for the final temperature by using this formula;

dt = T2 - T1

28.57 = T_{2} - 10\\\\T_{2} = 28.57 \; + \; 10\\\\T_{2} = 38.57

<em>Final temperature, T2 = 38.57°C</em>

<em>Therefore</em><em>, </em><em>the</em><em> final temperature </em><em>of the</em><em> water, T2</em> is equal to <em>38.57°C</em>

For more information visit: brainly.com/question/22736508

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4 0
3 years ago
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A student collected a total of 36.04 g of water from a reaction. What number of moles of water does this represent
umka21 [38]
To find the number of moles from a mass given, simply look to the formula n (moles) = m (mass, g) / MM (molar mass).
Mass was given, 36.04
Molar mass is the total atomic mass of all the atoms present. Water is H20, so that means 2 hydrogen and 1 oxygen. The atomic mass of hydrogen is 1 and atomic mass of oxygen is 16. Therefore MM= 1 + 1 + 16= 18.
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4 0
3 years ago
When 8.70 kJ of thermal energy is added to 2.50 mol of liquid methanol, it vaporizes. Determine the heat of vaporization in kJ/m
Anni [7]

Answer:

The heat of vaporisation of methanol is "3.48 KJ/Mol"

Explanation:

The amount of heat energy required to convert or transform  1 gram of liquid to vapour is called heat of vaporisation

When 8.7 KJ of heat energy is required to vaporize 2.5 mol of liquid methanol.

Hence, for 1 mol of liquid methanol, amount of heat energy required to evaporate the methanol is =   \frac{8.7}{2.5}KJ

 = 3.48 KJ

So, the heat of vaporization \delta H_{vap} = 3.48KJ/Mol

Therefore, the heat of vaporization of methanol is 3.48KJ/Mol

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3 years ago
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