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Sav [38]
4 years ago
13

PLLZZZ HEEEEEEELLLPPP

01%29" id="TexFormula1" title=" \frac{10x - 4}{2} + 7 = 5(x + 1)" alt=" \frac{10x - 4}{2} + 7 = 5(x + 1)" align="absmiddle" class="latex-formula">
​
Physics
2 answers:
Lady bird [3.3K]4 years ago
4 0

Answer:

hey is there

any options?

Nataliya [291]4 years ago
4 0
Any value of X
makes the equation true.
All real numbers
Interval Notation:
(
−
∞
,
∞
)
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angela uses a force of 25 newtons to lift her grocery bag while doing 50 joules of work. how far did she lift the grocery bags
Evgen [1.6K]
We know that:
W=Fs
50J=25N*s
s=50J/25N
s=2m
5 0
3 years ago
At constant pressure, the volume of a fixed mass of gas and its kelvin temperature are said to be
juin [17]
They are said to be directly related.

a) directly related.

This is Charles' Law.
3 0
4 years ago
Read 2 more answers
What is the ostrich's average acceleration from 9.0 to 18 seconds?
Sedaia [141]

The average acceleration from 9 to 18 seconds is 6 meters per second.

The graph shows that from 9 to 18 seconds the speed of the ostrich stays at a steady 6 meters per second.

6 0
3 years ago
Hen a gfci receptacle device is installed on a 20-ampere branch circuit (12 awg copper), what is the minimum volume allowance (i
Bezzdna [24]

Answer:

2.25in³

Explanation:

For a 12 awg conductor the minimum volume allowance as stated by the NEC is 2.25in³

See attached Table 314.16(B) from NEC 2011

4 0
3 years ago
the solubility product of lead fluoride is 3.6 x 10–8. what is its solubility in 0.10M NaF solution, in grams per liter
BartSMP [9]

Answer:

8.8 × 10⁻³ g/L

Explanation:

NaF is a strong electrolyte that ionizes according to the following reaction.

NaF(aq) → Na⁺(aq) + F⁻(aq)

Then, the concentration of F⁻ will also be 0.10 M.

In order to find the solubility of PbF₂ (S), we will use an ICE Chart.

        PbF₂(s) ⇄ Pb²⁺(aq) + 2 F⁻(aq)

I                           0                0.10

C                         +S               +2S

E                          S              0.10 + 2S

The solubility product (Kps) is:

Kps = 3.6 × 10⁻⁸ = [Pb²⁺].[F⁻]² = S . (0.10 + 2S)²

In the term 0.10 + 2S, 2S is negligible in comparison with 0.10 and we can omit it to simplify calculations.

Kps = 3.6 × 10⁻⁸ = S . (0.10)²

S = 3.6 × 10⁻⁵ M

The molar mass of PbF₂ is 245.20 g/mol. The solubility of PbF₂ in g/L is:

3.6 × 10⁻⁵ mol/L × 245.20 g/mol = 8.8 × 10⁻³ g/L

4 0
3 years ago
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