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Margaret [11]
3 years ago
14

True or False: Cooler objects always have more thermal energy than warmer objects.

Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0
False

Because you can see using a thermal camera I guess
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A battery powers a circuit for a small noisy fan. The fan’s motor gets warm as it turns. What energy transformations are taking
Snowcat [4.5K]

Answer:

The battery is an electric energy source, which is being used to power a motor. The motor turns this electricity into kinetic energy as it spins the fan, creates heat from friction, and creates noise as stated by the problem.

Explanation:

4 0
2 years ago
Read 2 more answers
Shrinking Loop. A circular loop of flexible iron wire has an initial circumference of 168 cm , but its circumference is decreasi
DedPeter [7]

Answer:

103.1 V

Explanation:

We are given that

Initial circumference=C=168 cm

\frac{dC}{dt}=-15cm/s

Magnetic field,B=0.9 T

We have to find the magnitude of the  emf induced in the loop after exactly time 8 s has passed since the circumference of the loop started to decrease.

Magnetic flux=\phi=BA=B(\pi r^2)

Circumference,C=2\pi r

r=\frac{C}{2\pi}

r=\frac{168}{2\pi} cm

\frac{dr}{dt}=\frac{1}{2\pi}\frac{dC}{dt}=\frac{1}{2\pi}(-15)=-\frac{15}{2\pi} cm/s

\int dr=-\int \frac{15}{2\pi}dt

r=-\frac{15}{2\pi}t+C

When t=0

r=\frac{168}{2\pi}

\frac{168}{2\pi}=C

r=-\frac{15}{2\pi}t+\frac{168}{2\pi}

E=-\frac{d\phi}{dt}=-\frac{d(B\pi r^2)}{dt}=-2\pi rB\frac{dr}{dt}

E=-2\pi(-\frac{5}{2\pi}t+\frac{168}{2\pi})B\times -\frac{15}{2\pi}

t=8 s

B=0.9

E=2\pi\times \frac{15}{2\pi}\times 0.9(-\frac{15}{2\pi}(8)+\frac{168}{2\pi})

E=103.1 V

6 0
3 years ago
3. A drill spins with a frequency of 1200 RPM (revolutions per minute). What is its
Damm [24]
Your answer is 20
just take 1,200 divided by 60 [second] :)
6 0
3 years ago
Read 2 more answers
For these pictures is more or less friction needed?
antiseptic1488 [7]

Answer:

8: More

9: More

10: More

11: Less

12: Less

12: More

4 0
2 years ago
Sketch a reaction progress curve for a reaction that has an activation energy of 22 kj and the total energy change is -103kj.
crimeas [40]

Answer:

Do find the answer in the attachment herein.

Explanation:

From the attached diagram:

I. Activation energy = Activated complex - ∆H(reactants)

Activation energy = 162-140 = 22Kj.

II. ∆H(reaction) = ∆H(products) - ∆H(reactants)

∆H(reaction) = 37 - 140 = -103Kj.

8 0
3 years ago
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