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3 years ago

All of the outer planets are much larger than the inner planets true or false

1 answer:

4 0

That statement is false because yes Jupiter and Saturn are large, however, planets like Uranus and Neptune are quite small if not smaller than some of the inner planets.

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A toy car having mass m = 1.50 kg collides inelastically with a toy train of mass M = 3.60 kg. Before the collision, the toy tra

baherus [9]

Answer:

$v_{f}$ = 3,126 m / s

Explanation:

In a crash exercise the moment is conserved, for this a system formed by all the bodies before and after the crash is defined, so that the forces involved have been internalized.

the car has a mass of m = 1.50 kg a speed of v1 = 4.758 m / s and the mass of the train is M = 3.60 kg and its speed v2 = 2.45 m / s

Before the crash

p₀ = m v₁₀ + M v₂₀

After the inelastic shock

$p_{f}$ = m $v_{1f}$ + M $v_{2f}$

p₀ = $p_{f}$

m v₀ + M v₂₀ = m $v_{1f}$ + M $v_{2f}$

We cleared the end of the train

M $v_{2f}$ = m (v₁₀ - v1f) + M v₂₀

Let's calculate

3.60 v2f = 1.50 (2.15-4.75) + 3.60 2.45

$v_{2f}$ = (-3.9 + 8.82) /3.60

$v_{2f}$ = 1.36 m / s

As we can see, this speed is lower than the speed of the car, so the two bodies are joined

set speed must be

m v₁₀ + M v₂₀ = (m + M) $v_{f}$

$v_{f}$ = (m v₁₀ + M v₂₀) / (m + M)

$v_{f}$ = (1.50 4.75 + 3.60 2.45) /(1.50 + 3.60)

$v_{f}$ = 3,126 m / s

4 0

4 years ago

If at 10m above the ground an object has 50J of Kinetic Energy, with 50J of Potential Energy. How high can the object travel?

steposvetlana [31]

Hi there!

$\large\boxed{\text{B) 20 meters}}$

We know that:

$E_T = U + K$

U = Potential Energy (J)

K = Kinetic Energy (J)

E = Total Energy (J)

At 10m, the total amount of energy is equivalent to:

U + K = 50 + 50 = 100 J

To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:

100J = mgh

We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².

50J = 10(10)m

m = 1/2 kg

Now, solve for height given that E = 100 J:

100J = 1/2(10)h

100J = 5h

<u>h = 20 meters</u>

3 0

3 years ago

I don’t understand can someone break it down for me

Westkost [7]

Answer:

a = (v² – v₀²)/ 2(s – s₀)

Explanation:

v² = v₀² + 2a (s – s₀)

We can make 'a' the subject of the above expression as follow:

v² = v₀² + 2a (s – s₀)

Subtract v₀² from both side

v² – v₀² = v₀² + 2a (s – s₀) – v₀²

v² – v₀² = v₀² – v₀² + 2a (s – s₀)

v² – v₀² = 2a (s – s₀)

Divide both side by (s – s₀)

(v² – v₀²)/ (s – s₀) = 2a

Divide both side by 2

(v² – v₀²)/ (s – s₀) ÷ 2 = a

(v² – v₀²)/ (s – s₀) × 1/2 = a

(v² – v₀²)/ 2(s – s₀) = a

a = (v² – v₀²)/ 2(s – s₀)

6 0

3 years ago

An object is in uniform circular motion, tracing an angel at 30 degrees every 0.010 seconds. What's the period of this motion an

Neko [114]

Here's the rule you need to know
in order to answer this question:

   1 full circle ==> 360 degrees .

Got that ?

Now you could set up a proportion:

   (30 degrees) / (0.01 second) = (360 degrees) / (time for full period)

Cross-multiply the proportion:

   (30°) · (period) = (360°) · (0.01 sec)

Divide each side by (30°) : Period = (360° · 0.01 sec) / (30°)

   = (3.6° · sec) / (30°)

   = (3.6 / 30) sec

   = 0.12 sec .
___________________________________

Another way to look at it:

30° takes 0.01 second
60°     takes 0.02 second
90°     takes 0.03 second
120° takes 0.04 second
150° takes 0.05 second
180° takes 0.06 second
210° takes 0.07 second
240° takes 0.08 second
270° takes 0.09 second
300° takes 0.10 second
330° takes 0.11 second
360° takes   0.12 second

7 0

4 years ago

What is electrical circuit

n200080 [17]

Path for transmitting electric current. An electric circuit includes a device that gives energy to the charged particles constituting the current, such as battery or a generator; devices that use current, such as lamps, electric motors, or computers; and the connecting wires or transmission lines

5 0

4 years ago