All of the outer planets are much larger than the inner planets true or false
1 answer:
You might be interested in
Answer:
a) x_average = ∑ / n
, b) Δx_{i} = x_{i} –x_average,
d) σ = √(1/n-1 ∑ Dx_{i}² )
Explanation:
Some definitions are requested
a) the average value is the sum of all the values divided by the number of them, if the uncertainties are random, this is the closest value to the real one
x_average = ∑ / n
b) The deviation from the mean value or absolute error is the measured value minus the average value
Δx_{i} = x_{i} –x_average
c) is the average value of the deviations
Δx_average = ∑ Δx_{i} / n
d) It is a measure of the dispersion of the values with respect to their average value, it takes the worst of all cases, widely used for large numbers of data
σ = √(1/n-1 ∑ Dx_{i}² )
Experimental results should be given as follows
Average value ± uncertainty and the standard deviation
(x_average + - Δx_average)
σ
r₁ = distance of point A from charge q₁ = 0.13 m
r₂ = distance of point A from charge q₂ = 0.24 m
r₃ = distance of point A from charge q₃ = 0.13 m
Electric field by charge q₁ at A is given as
E₁ = k q₁ /r₁² = (9 x 10⁹) (2.30 x 10⁻¹²)/(0.13)² = 1.225 N/C towards right
Electric field by charge q₂ at A is given as
E₂ = k q₂ /r₂² = (9 x 10⁹) (4.50 x 10⁻¹²)/(0.24)² = 0.703 N/C towards left
Since the electric field in left direction is smaller, hence the electric field by the third charge must be in left direction
Electric field at A will be zero when
E₁ = E₂ + E₃
1.225 = 0.703 + E₃
E₃ = 0.522 N/C
Electric field by charge "q₃" is given as
E₃ = k q₃ /r₃²
0.522 = (9 x 10⁹) q₃/(0.13)²
q₃ = 0.980 x 10⁻¹² C = 0.980 pC
