I really need help with this question someone plz help !

What is the net work done on the 20kg block while it moves the 4 meters?

Vinil7 [7]

Answer:

The answer to your question is 784.8 J. None of your answer, did you forget some information?

Explanation:

Data

mass = 20 kg

distance = 4 m

work = ?

Formula

Work = force x distance

Force = mass x gravity

Process

1.- Calculate the weight of the block

Weight = 20 x 9.81

Weight = 196.2 N

2.- Calculate the work done

Work = 196.2 x 4

Work = 784.8 J

5 0

3 years ago

A 0.250 kgkg toy is undergoing SHM on the end of a horizontal spring with force constant 300 N/mN/m. When the toy is 0.0120 mm f

konstantin123 [22]

Answer:

(a) The total energy of the object at any point in its motion is 0.0416 J

(b) The amplitude of the motion is 0.0167 m

(c) The maximum speed attained by the object during its motion is 0.577 m/s

Explanation:

Given;

mass of the toy, m = 0.25 kg

force constant of the spring, k = 300 N/m

displacement of the toy, x = 0.012 m

speed of the toy, v = 0.4 m/s

(a) The total energy of the object at any point in its motion

E = ¹/₂mv² + ¹/₂kx²

E = ¹/₂ (0.25)(0.4)² + ¹/₂ (300)(0.012)²

E = 0.0416 J

(b) the amplitude of the motion

E = ¹/₂KA²

$A = \sqrt{\frac{2E}{K} } \\\\A = \sqrt{\frac{2*0.0416}{300} } \\\\A = 0.0167 \ m$

(c) the maximum speed attained by the object during its motion

$E = \frac{1}{2} mv_{max}^2\\\\v_{max} = \sqrt{\frac{2E}{m} } \\\\v_{max} = \sqrt{\frac{2*0.0416}{0.25} } \\\\v_{max} = 0.577 \ m/s$

8 0

3 years ago

Suppose that the magnetic field in some region has the form B = kz ˆx (where k is a constant). Find the force on a square loop (

AleksAgata [21]

Answer:

$F = ika^2$

Explanation:

As we know that loop is placed in YZ plane and magnetic field is along x direction

So here net force on the side of the loop which lies along Y axis is given as

$F_1 = i (\vec L \times \vec B)$

here we know that on Y axis z = 0

so B = 0

so we have

$F_1 = 0$

now on the opposite side we have z = a

so magnetic field is given as

$B = ka$

so force on that side is given as

$F = i(\vec L \times \vec B)$

$F = i(a)(ka) sin90$

$F_2 = ika^2$

so net force on the loop is given as

$F = F_1 + F_2$

$F = ika^2$

5 0

3 years ago

An object that has a mass of 36.0kg is pushed along a horizontal surface with a force of 85.0N. IF

Oksana_A [137]

Answer:

0.36m/s^2

Explanation:

a=f/m

7 0

3 years ago

Why cant soy sauce freeze

juin [17]

The salt content in soy

8 0

3 years ago

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