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Ede4ka [16]
3 years ago
12

Which type of energy is released when a nucleus is split apart

Physics
1 answer:
gayaneshka [121]3 years ago
3 0
Nuclear energy comes from nucleus of atoms which is released by nucleus fusion
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Kraig pulls a box to the right at an angle of 40 degrees to the horizontal with a force of 30 Newtons. If Kraig pulls the box a
eimsori [14]

Answer:

459.6J

Explanation:

Given parameters:

Angle of pull  = 40°

Force applied  = 30N

Distance moved = 20m

Unknown:

Work done by Kraig  = ?

Solution:

To solve this problem;

   Work done  = F x dcosФ

d is the distance

F is the force

Ф is the angle given

  Work done  = 30 x 20cos40°   = 459.6J

3 0
3 years ago
Scientists have discovered convection currents inside Earth. Explain how these convection currents move and what layer(s) they o
fgiga [73]

Answer:

I don't know what to do

Explanation:

So

7 0
4 years ago
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Una grúa está subiendo una caja de 1000 kg atada a una cadena. La caja, que inicialmente está en reposo, incrementa su velocidad
BabaBlast [244]

Answer:

40 metros en 10 segundos.

Explicación:

Una grúa está levantando una caja de 1000 kg atada a una cadena y la caja, que inicialmente está en reposo, aumenta su velocidad en 4 m / s por segundo, por lo que si la región de colocación está a 40 metros de distancia, la grúa tarda 10 segundos en completar el proceso. tarea de movimiento y colocación de la caja. La grúa se utiliza para levantar y mover cargas pesadas, máquinas, materiales y mercancías para diferentes propósitos. Entonces el trabajo realizado por la grúa depende de la velocidad y la distancia de colocación.

3 0
4 years ago
A car initially traveling at 27.2 m/s undergoes a constant negative acceleration of magnitude 1.90 m/s2 after its brakes are app
zubka84 [21]

Answer:

Therefore, the revolutions that each tire makes is:

\Delta \theta=22\: rev

Explanation:

We can use the following equation:

\omega_{f}^{2}=\omega_{i}^{2}-2\alpha \Delta \theta (1)

The angular acceleration is:

a_{tan}=\alpha R

\alpha=\frac{1.9}{0.325}

\alpha=5.85\: rad/s^{2}

and the initial angular velocity is:

\omega_{i}=\frac{v}{R}

\omega_{i}=\frac{27.2}{0.325}

\omega_{i}=83.69\: rad/s

Now, using equation (1) we can find the revolutions of the tire.

0=83.69^{2}-2*25.85 \Delta \theta

\Delta \theta=135.47\: rad

Therefore, the revolutions that each tire makes is:

\Delta \theta=22\: rev

I hope it helps you!

6 0
3 years ago
What type of wave would michael produce by shaking his finger back and forth twenty-five times per second?
STatiana [176]
B. a sound wave that he could just barely hear
4 0
4 years ago
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