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Lelechka [254]
4 years ago
9

We learned about three career opportunities in the field of pulp and paper in class. Pick one career and find out the education,

training, and experience required for this profession. Write about what you found and explain why this profession might interest you
Chemistry
1 answer:
nekit [7.7K]4 years ago
8 0

Answer:

Pulp and Paper technology is a specialist field of chemical engineering which involves the study of the processes required for the conversion of raw materials such as wood, into pulp and paper products.

Paper and pulp manufacturing is a growing and dynamic industry so it requires a wide variety of personnel - from unskilled and semi-skilled workers to tradesmen, technicians and engineers - to control all the processes and develop new ones.

I choose to be a chemist in the field of paper and pulp. Requirements and compulsory Subjects: Physical Sciences, Mathematics, Engiineering and Technology.

Chemists are responsible for quality control and they study the influence of various chemicals on pulp and paper. Chemical and mechanical engineers develop new production methods.

I'll like to be a chemist in the field of paper and pulp because they perform the major role in the chemical properties of the paper and pulp.

Explanation:

Hope it helps.

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Explanation:

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<em>So</em><em>,</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>state</em><em> </em><em>that</em><em> </em><em>the</em><em> </em><em>relationship</em><em> </em><em>between</em><em> </em><em>them</em><em> </em><em>are</em><em> </em><em>directly</em><em> </em><em>proportional</em><em>. </em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Explanation:

hope this helps! good luck :)

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A 25 mL sample of 0.100 M HNO3 completely reacts with NaOH according to this equation:
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Answer:

2.5x10^–3 mole.

Explanation:

Data obtained from the question include:

Volume of solution = 25mL

Molarity of HNO3 = 0.1M

Mole of HNO3 =..?

First, we'll begin by converting 25mL to L. This can be achieved by doing the following:

1000mL = 1L

Therefore, 25mL = 25/1000 = 0.025L

Now, we can obtain the number of mole of HNO3 present in the solution as follow:

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Therefore, 2.5x10^–3 mole of HNO3 is present in the solution.

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