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Lelechka [254]
3 years ago
9

We learned about three career opportunities in the field of pulp and paper in class. Pick one career and find out the education,

training, and experience required for this profession. Write about what you found and explain why this profession might interest you
Chemistry
1 answer:
nekit [7.7K]3 years ago
8 0

Answer:

Pulp and Paper technology is a specialist field of chemical engineering which involves the study of the processes required for the conversion of raw materials such as wood, into pulp and paper products.

Paper and pulp manufacturing is a growing and dynamic industry so it requires a wide variety of personnel - from unskilled and semi-skilled workers to tradesmen, technicians and engineers - to control all the processes and develop new ones.

I choose to be a chemist in the field of paper and pulp. Requirements and compulsory Subjects: Physical Sciences, Mathematics, Engiineering and Technology.

Chemists are responsible for quality control and they study the influence of various chemicals on pulp and paper. Chemical and mechanical engineers develop new production methods.

I'll like to be a chemist in the field of paper and pulp because they perform the major role in the chemical properties of the paper and pulp.

Explanation:

Hope it helps.

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Answer:

P(total pressure) = 504 mmHg = 504mm/760mm/atm = 0.663 atm

Explanation:

Apply Dalton's Law of Partial Pressures.

P(total) = ∑Partial Pressures = ∑(256mm + 198mm + 48mm) = 504 mmHg

P(total pressure) = 504 mmHg = 504mm/760mm/atm = 0.663 atm

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Propane is often used to heat homes. The combustion of propane follows the following reaction: C3H8(g) + 5O2(g)  3CO2 (g) + 4H
swat32

Answer:

To release 7563 kJ of heat, we need to burn 163.17 grams of propane

Explanation:

<u>Step 1</u>: Data given

C3H8 + 5O2 -----------> 3CO2 + 4H2O      ΔH° = –2044 kJ

This means every mole C3H8

Every mole of C3H8 produces 2044 kJ of heat when it burns (ΔH° is negative because it's an exothermic reaction)

<u>Step 2: </u>Calculate the number of moles to produce 7563 kJ of heat

1 mol = 2044 kJ

x mol = 7563 kJ

x = 7563/2044 =  3.70 moles

To produce 7563 kJ of heat we have to burn 3.70 moles of C3H8

<u>Step 3: </u>Calculate mass of propane

Mass propane = moles * Molar mass

Mass propane = 3.70 moles * 44.1 g/mol

Mass propane = 163.17 grams

To release 7563 kJ of heat, we need to burn 163.17 grams of propane

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I think it might be B
Explanation
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