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Alex777 [14]
3 years ago
11

d. The force is doubled and the object’s mass is halved? 18. ||| A man pulling an empty wagon causes it to accelerate at 1.4 m/s

2. What will the acceleration be if he pulls with the same force when the wagon contains a child whose mass is three times that of the wagon?
Physics
1 answer:
Harrizon [31]3 years ago
8 0

Answer:

a' = 0.35 m/s^2

Explanation:

Let say the empty wagon has mass "M"

now by newton's II Law we will have

F = Ma

now it is given that empty wagon is pulled with acceleration 1.4 m/s/s

now we will have

F = 1.4 M

now a child of mass three times the mass of wagon is sitting on the empty wagon

so here we have

F = (M + 3M) a

1.4 M = 4M a'

so we have

a' = 0.35 m/s^2

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U = mgy
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8 0
3 years ago
A laser beam is incident at an angle of 33.0° to the vertical onto a solution of cornsyrup in water.(a) If the beam is refracted
IrinaK [193]

Answer:

1.29649

488.08706 nm

6.14644\times 10^{14}\ Hz

231715700.28346 m/s

Explanation:

n denotes refractive index

1 denotes air

2 denotes solution

\lambda_0 = 632.8 nm

From Snell's law we have the relation

n_1sin\theta_1=n_2sin\theta_2\\\Rightarrow n_2=\dfrac{n_1sin\theta_1}{sin\theta_2}\\\Rightarrow n_2=\dfrac{1\times sin33}{sin24.84}\\\Rightarrow n_2=1.29649

Refractive index of the solution is 1.29649

Wavelength is given by

\lambda=\dfrac{\lambda_0}{n_2}\\\Rightarrow \lambda=\dfrac{632.8}{1.29649}\\\Rightarrow \lambda=488.08706\ nm

The wavelength of the solution is 488.08706 nm

Frequency is given by

f=\dfrac{c}{\lambda}\\\Rightarrow f=\dfrac{3\times 10^8}{488.08706\times 10^{-9}}\\\Rightarrow f=6.14644\times 10^{14}\ Hz

The frequency is 6.14644\times 10^{14}\ Hz

v=\dfrac{c}{n_2}\\\Rightarrow v=\dfrac{3\times 10^8}{1.29469}\\\Rightarrow v=231715700.28346\ m/s

The speed in the solution is 231715700.28346 m/s

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Answer:

Draw a free-body diagram to show all forces acting on the object.

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Answer:

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