Question

A positive charge of 6.0 x 10-4 C is in an electric field that exerts a force of 4.5 x 10 -4 on it. What is the strength of the electric field?

Answer 1

Electric field is defined as force per unit charge.

So it is given by

$F = q E$

now we can find electric field by

$E = \frac{F}{q}$

$E = \frac{4.5*10^{-4}}{6 * 10^{-4}}$

$E = 0.75 N/C$

So field strength is 0.75 N/C.