Two objects each moving with speed v travel in opposite directions along a straight line passing through both their centers. The
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Answer:
63.8 V
Explanation:
We are given that
Potential difference,V=140 V
We know that
According to question
In series
Potential across 1.2 square cm=
Hence, the voltage across the 1.2 square cm wire=63.8 V
Answer:
The answer to the question is;
The rate at which the distance between the two cars is changing is equal to 14.4 ft/sec.
Explanation:
We note that the distance traveled by each car after 4 seconds is
Car A = 19 ft in the west direction.
Car B = 26 ft in the north direction
The distance between the two cars is given by the length of the hypotenuse side of a right angled triangle with the north being the y coordinate and the west being the x coordinate.
Therefore, let the distance between the two cars be s
we have
s² = x² + y²
= (19 ft)² + (26 ft)² = 1037 ft²
s = = 32.202 ft.
The rate of change of the distance from their location 4 seconds after they commenced their journeys is given by;
Since s² = x² + y² we have
→ which gives
We note that the speeds of the cars were given as
Car B moving north = 12 ft/sec, which is the y direction and
Car A moving west = 8 ft/sec which is the x direction.
Therefore
= 12 ft/sec and
= 8 ft/sec
becomes
= 464 ft²/sec
= 14.409 ft/sec ≈ 14.4 ft/sec to one place of decimal.