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ankoles [38]
3 years ago
9

PLEASE HELP!!!After a gas-filled balloon is released, it rises 90 feet by the end of the first minute. By the end of the second

minute, the balloon rises 120 feet, and by the end of the third minute, it rises 150 feet. How many feet would the balloon rise in 8 minutes?. a.. . 300. . c.. . 390. b.. . 330. . d.. . 660
Physics
2 answers:
fiasKO [112]3 years ago
5 0
The situation is an example of an arithmetic progression through the data 90, 120, 150, .. . In this case, the arithmetic difference is 30. The expression that applies here is an = 90 + 30 * (n - 1) where n is the order of the term to be determined. If n is 8, then  the height is equal to a. 300 feet.
ivanzaharov [21]3 years ago
4 0

Answer:

A

Explanation:

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A 10,000kg space ship is orbiting the moon with a radius of 25km from the ship to the center of the moon. It's tangential speed
galina1969 [7]

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False

Explanation:

ac = v^2/r

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3 years ago
A student pushes a laptop cart down the hallway by applying 20 Newtons force. The student pushes it 10 meters and
noname [10]

Answer:

None.

Explanation:

  • By definition, work is a process that it happens when an applied force

        causes an object to change its position, i.e. to have a displacement.

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An object of mass 2 kg travels through outer space in a straight line at a constant
slava [35]

Answer:

b. It is subject to a net force of zero

Explanation:

F = m*a

F = force

m = mass

a = acceleration

Since the object is moving at a constant velocity not speeding up or slowing down and moving in a sight line. All the forces that are acting on the object are canceling each other out so the answer is:

b. It is subject to a net force of zero

7 0
3 years ago
At the instant the traffic light turns green, a car starts with a constant acceleration of 3.00 ft/s^2. At the same instant a tr
DedPeter [7]

Answer:

The car overtakes the truck at a distance d = 3266.2ft from the starting point

Explanation:

Problem Analysis

When car catches truck:

dc = dt = d

dc: car displacement

dt: truck displacement

tc = tt = t

tc: car time

tt : truck time

car kinematics :

car moves with uniformly accelerated movement:

d = vi*t + (1/2)a*t²

vi = 0 : initial speed

d = (1/2)*a*t² Equation (1)

Truck kinematics:

Truck moves with constant speed:

d = v*t Equation (2)

Data

We know that the acceleration of the car is 3.00 ft / s² and the speed of the truck is 70.0 ft / s .

Development problem

Since the distance traveled by the car is equal to the distance traveled by the truck and the time elapsed is the same for both, then we equate equations (1 ) and (2)

Equation (1) = Equation (2)

(1/2)*a*t² = v*t

(1/2)*3*t² = 70*t  (We divide both sides by t)

1.5*t = 70

t = 70 ÷ 1.5

t = 46.66 s

We replace t = 46.66 s in equation (2) to calculate d:

d = 70*46.66 = 3266.2ft

d = 3266.2 ft

5 0
3 years ago
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