2 years ago

Have the highest birth rate

Physics

1 answer:

Sveta_85 [38]2 years ago

3 0

Answer:

353225

Explanation:8uhhhhhhhhhlkgg

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Which factors could be potential sources of error in the experiment? check all that apply.

Vadim26 [7]

(A)energy lost in the lever due to friction

(C) visual estimation of height of the beanbag

(E)position of the fulcrum for the lever affecting transfer of energy

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3 years ago

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A man ties one end of a strong rope 8.17 m long to the bumper of his truck, 0.524 m from the ground, and the other end to a vert

Kamila [148]

Answer:

2442.5 Nm

Explanation:

Tension, T = 8.57 x 10^2 N

length of rope, l = 8.17 m

y = 0.524 m

h = 2.99 m

According to diagram

Sin θ = (2.99 - 0.524) / 8.17

Sin θ = 0.3018

θ = 17.6°

So, torque about the base of the tree is

Torque = T x Cos θ x 2.99

Torque = 8.57 x 100 x Cos 17.6° x 2.99

Torque = 2442.5 Nm

thus, the torque is 2442.5 Nm.

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3 years ago

a horse began running due east and covered 25km in 4.0 hours what is the average velocity of the horse

Komok [63]

25km / 4hr = <em>6.25 km/hr east</em>

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2 years ago

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An electric field is produced by the very long, uniformly charged rod drawn above. If the strength of the electric field is E1 a

Debora [2.8K]

Answer: hello the complete question is attached below

answer :

r2 = 4r1

Explanation:

Electric field strength = F / q

we will assume the rod has an infinite length

For an infinitely charged rod

E ∝ 1/ r

considering two electric fields E1 and E2 at two different locations as described in the question

E1/E2 = r1/r2 ----- ( 2 )

<u>Calculate for r2 when E2 = E1/4 </u>

back to equation 2

E1 / (E1/4) = r1 / r2

∴ r2 = 4r1

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2 years ago

A 6 cm object is 15 cm from a convex lens that has a focal length of 5 cm. What is the distance of the image from the lens, to t

Vesna [10]

Answer:

7.50 cm

Explanation:

The formula

1/v + 1/u = 1/f

Is used.

where.

u is the object distance.

v is the image distance.

f is the focal length of the lens.

1/v + 1/15 = 1/5

1/v = 1/5 - 1/15

1/v = (3-1)/15

1/v = 2/15

2v = 15

V = 15/2

V = 7.5 cm

For focal length, f in lens is always taken as negative for concave and positive for convex. ... And for image distance, V in lens it is taken as positive in Convex lens since image is formed on +X side. It is taken as negative in Concave lens since image is formed in -X side of the Cartesian.

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