Answer:
Frequency is ![213.04\ s^{-1}.](https://tex.z-dn.net/?f=213.04%5C%20s%5E%7B-1%7D.)
Explanation:
Distance between source 1 from the receiver , ![S_1 =\sqrt{10^2+22^2}=24.17\ m.](https://tex.z-dn.net/?f=S_1%20%3D%5Csqrt%7B10%5E2%2B22%5E2%7D%3D24.17%5C%20m.)
Distance between source 2 from the receiver , ![S_2=\sqrt{5^2+22^2}=22.56\ m.](https://tex.z-dn.net/?f=S_2%3D%5Csqrt%7B5%5E2%2B22%5E2%7D%3D22.56%5C%20m.)
Now ,
Path difference , ![r = S_1-S_2=24.17-22.56=1.61\ m.](https://tex.z-dn.net/?f=r%20%3D%20S_1-S_2%3D24.17-22.56%3D1.61%5C%20m.)
We know, for constructive interference path difference should be integral multiple of wavelength .
Therefore, ![r=n\times \lambda](https://tex.z-dn.net/?f=r%3Dn%5Ctimes%20%5Clambda)
It is given that n = 1,
Therefore, ![\lambda=1.61\ m.](https://tex.z-dn.net/?f=%5Clambda%3D1.61%5C%20m.)
Frequency can be found by , ![\nu=\dfrac{v}{\lambda}= \dfrac{343}{1.61}= 213.04\ s^{-1} .](https://tex.z-dn.net/?f=%5Cnu%3D%5Cdfrac%7Bv%7D%7B%5Clambda%7D%3D%20%5Cdfrac%7B343%7D%7B1.61%7D%3D%20%20%20213.04%5C%20s%5E%7B-1%7D%20.)
Hence, this is the required solution.
The absolute pressure is given by the equation,
![P_{abs}=P_{atm}-P_{vac}](https://tex.z-dn.net/?f=P_%7Babs%7D%3DP_%7Batm%7D-P_%7Bvac%7D)
Here,
is absolute pressure,
is atmospheric pressure and
is vacuum pressure.
Therefore,
![P_{abs}=98 kPa-80 kPa=18kPa](https://tex.z-dn.net/?f=P_%7Babs%7D%3D98%20kPa-80%20kPa%3D18kPa)
The gage pressure is given by the equation,
.
Thus,
.
In kn/m^2,
The absolute pressure,
![P_{abs}=18kPa(\frac{1kN/m^2}{kPa}) =18\ kN/m^2](https://tex.z-dn.net/?f=P_%7Babs%7D%3D18kPa%28%5Cfrac%7B1kN%2Fm%5E2%7D%7BkPa%7D%29%20%3D18%5C%20kN%2Fm%5E2)
The gage pressure,
.
In lbf/in2
The absolute pressure,
![P_{abs}=18\ kPa(\frac{1.45\times 10^{-1}\ lbf/in^2 }{1kPa} )=2.6\ lbf/in^2](https://tex.z-dn.net/?f=P_%7Babs%7D%3D18%5C%20kPa%28%5Cfrac%7B1.45%5Ctimes%2010%5E%7B-1%7D%5C%20lbf%2Fin%5E2%20%7D%7B1kPa%7D%20%29%3D2.6%5C%20lbf%2Fin%5E2)
The gage pressure,
![P_{gage}=-80kPa(\frac{1.45\times 10^{-1}\ lbf/in^2 }{1kPa} )=-11.6\ lbf/in^2](https://tex.z-dn.net/?f=P_%7Bgage%7D%3D-80kPa%28%5Cfrac%7B1.45%5Ctimes%2010%5E%7B-1%7D%5C%20lbf%2Fin%5E2%20%7D%7B1kPa%7D%20%29%3D-11.6%5C%20lbf%2Fin%5E2)
In psi,
The absolute pressure,
.
The gage pressure,
![P_{gage}=-80kPa(\frac{1.45037738\times 10^{-1}\ psi }{1kPa} )=-11.6030\ psi](https://tex.z-dn.net/?f=P_%7Bgage%7D%3D-80kPa%28%5Cfrac%7B1.45037738%5Ctimes%2010%5E%7B-1%7D%5C%20psi%20%7D%7B1kPa%7D%20%29%3D-11.6030%5C%20psi)
In mm Hg
The absolute pressure,
![P_{abs}=18kPa(\frac{7.5\ mm\ of\ Hg }{1\ kPa})= 135\ mm\ of\ Hg](https://tex.z-dn.net/?f=P_%7Babs%7D%3D18kPa%28%5Cfrac%7B7.5%5C%20mm%5C%20of%5C%20Hg%20%7D%7B1%5C%20kPa%7D%29%3D%20135%5C%20mm%5C%20of%5C%20Hg)
The gage pressure,
![P_{gage}=-80kPa(\frac{7.5\ mm\ of\ Hg }{1\ kPa})=-600\ mm\ of\ Hg](https://tex.z-dn.net/?f=P_%7Bgage%7D%3D-80kPa%28%5Cfrac%7B7.5%5C%20mm%5C%20of%5C%20Hg%20%7D%7B1%5C%20kPa%7D%29%3D-600%5C%20mm%5C%20of%5C%20Hg)
Answer:
Red photons have the least amount of energy
Explanation:
The relationship between the photon energy and the color of light is given by:
![E=\frac{hc}{\lambda}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7Bhc%7D%7B%5Clambda%7D)
where
E is the energy
h is the Planck constant
c is the speed of light
is the wavelength (which determines the color of light)
As we see from the equation, energy and wavelength are inversely proportional: this means that the longer the wavelength, the lower the energy, and viceversa.
Among the colors in the visible light spectrum, red is the color with longest wavelength (620-750 nm) and violet is the color with shortest wavelength (380-450 nm). This means that red photons have the least amount of energy, while violet photons have the greatest amount of energy.
So the correct choice is
Red photons have the least amount of energy
APPARENT MOTION- <span>the sensation of seeing movement when nothing actually moves in the environment, as when two neighbouring lights are switched on and off in rapid <span>succession.</span></span>