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Delicious77 [7]
3 years ago
8

How can shoe and tire marks be preserved in mud?

Physics
1 answer:
Svetach [21]3 years ago
4 0
I believe it is b
Hope I helped!
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When you trace the outline of your palm how do you find its area​
Tcecarenko [31]

Answer:

you count the squares or messure it

Explanation:

you can raw equal squares about 1 cm wide if possible all equal and count the squares eg theres 10 squares (small hand) so that would be 10cm squared

7 0
3 years ago
Read 2 more answers
A wooden plaque is in the shape of an ellipse with height 30 centimeters and width 22 centimeters. Find an equation for the elli
Volgvan

Answer:

Explanation:

height of Ellipse =30 cm  

i.e. 2 a=30

Width of Ellipse =22 cm

i.e. 2 b=22

Equation of a vertical Ellipse is

\frac{x^2}{b^2}+\frac{y^2}{a^2}=1

a=15 ,b =11

\frac{x^2}{11^2}+\frac{y^2}{15^2}=1

at y=4 cm

\frac{x^2}{11^2}+\frac{4^2}{15^2}=1  

x=\frac{11}{15}\times \sqrt{15^2-4^2}

x=10.6 cm  

5 0
3 years ago
What are the steps to extract metal from the earths crust
Pani-rosa [81]
<span>Methods of extraction include: extract by electrolysis, extract by reaction with carbon or carbon monoxide, and extracted by various chemical reactions.</span>
4 0
3 years ago
A constant friction force of 25 N acts on a 65-kg skier for 15 s on level snow. What is the skier’s change in velocity
nikdorinn [45]

Answer:

\Delta v=5.77m/s

Explanation:

Newton's 2nd Law relates the net force <em>F</em> on an object of mass <em>m </em>with the acceleration <em>a</em> it experiments by <em>F=ma.</em> In our case the net force is the friction force, since it's the only one the skier is experimenting horizontally and the vertical ones cancel out since he's not moving in that direction. Our acceleration then will be:

a=\frac{F}{m}

Also, acceleration is defined by the change of velocity \Delta v in a given time t, so we have:

a=\frac{\Delta v}{t}

Since we want the change in velocity, <em>mixing both equations</em> we conclude that:

\Delta v=at=\frac{Ft}{m}

Which for our values means:

\Delta v=\frac{Ft}{m}=\frac{(25N)(15s)}{(65Kg)}=5.77m/s

4 0
3 years ago
A squirrel on a table clothesline is running 3.4 m./s. How far does the squirrel go in 2.5 minutes
statuscvo [17]
2.5 that would be the corect answer hope this helps
5 0
3 years ago
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