Answer:
The glass transition occur when the given temperature gets drop below the temperature of the glass transition for the polymers. During the creases of the long range of the given motion, the polymer start changing from the state of hard into the form of brittle.
The range of the glass transition temperature are between the 0 to -150°C. The basic use of the polymer is basically depend upon the main properties of the polymer.
Answer:
Efficient when the marginal benefits of project = marginal costs of project.
Explanation:
Majority Decision Rule:
Majority decision rule is based on the notion of equality. An alternative is selected which has majority of votes. The simple majority decision rule may generate efficient results if the marginal benefits of a project are equal or greater than the marginal costs of the project.
Technician A is correct. Technician B is wrong because a gear's transmission is used to increase or decrease torque.
The relation torque is relying on multiplying the circumferential detail with the resource of the usage of the radius; massive gears experience a greater amount of torque, at the same time as smaller gears experience a great deal much less torque. Similarly, the torque ratio is equal to the ratio of the gears' radii. A gear's transmission torque modifications as it will boom or decreases speed. Commonly, with the resource of the usage of lowering the speed, a small torque on the doorway issue is transferred as a massive torque at the output issue. The calculation of torque is quantified with the resource of the usage of an extensive form of teeth.
Learn more about the torque at brainly.com/question/28220969
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It would have environmental and societal impacts
Answer:
See explaination
Explanation:
#include <iostream>
#include<string.h>
using namespace std;
bool isPalindrome(string str, int lower, int upper){
if(str.length() == 0 || lower>=upper){
return true;
}
else{
if(str.at(lower) == str.at(upper)){
return isPalindrome(str,lower+1,upper-1);
}
else{
return false;
}
}
}
int main(){
string input;
cout<<"Enter string: ";
cin>>input;
if(isPalindrome(input,0,input.length()-1)){
cout<<input<<" is a palindrome"<<endl;
}
else{
cout<<input<<" is NOT a palindrome"<<endl;
}
return 0;
}
