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iVinArrow [24]
3 years ago
9

Which energy source would you rank as the best option for the rescue team? Why?

Engineering
1 answer:
Molodets [167]3 years ago
7 0
B.

Combustion engine driving a standby electrical generator.
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What does an aeronautical engineer design
Colt1911 [192]

Answer:

they work with aircraft, designing aircrafts.

Explanation:

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3 years ago
True or false? if i were to hook up an ac voltage source to a resistor, the voltage drop across the resistor would be in phase w
hodyreva [135]

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Explanation:

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Assume (for simplicity in this exercise) that only one tuple fits in a block and memory holds at most three blocks. Show the run
den301095 [7]

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See explaination

Explanation:

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Take a look at the attached file for a further detailed and step by step solution of the given problem.

6 0
3 years ago
An electrical heater is a form of sensible heating process, and heats 0.1m/s of air from 15°C and 80% RH to 50°C? The barometric
lawyer [7]

Answer:

The heater load =35 KJ/kg

Explanation:

Given that

At initial condition

Temperature= 15°C

RH=80%

At final condition

Temperature= 50°C

We know that in sensible heating process humidity ratio remain constant.

Now from chart

At temperature= 15°C and RH=80%

h_1=38 \frac{KJ}{kg},v=0.8 \frac{m^3}{kg}

At  temperature= 50°C

h_2=73 \frac{KJ}{kg}

So\ the\ heater\ load =h_2-h_1

The heater load = 73 - 38 KJ/kg

The heater load =35 KJ/kg

3 0
3 years ago
A 800-MW steam power plant, which is cooled by a nearby river, has a thermal efficiency of 40 percent. Determine the rate of hea
Arturiano [62]

Answer:

Rate of heat transfer to river=1200MW

So the actual amount of heat rejected ti the river will be less as there will some heat loss to surrounding and in pipes

Explanation:

In order to find the actual heat transfer rate is lower or higher than its value we will first find the rate of heat transfer to power plant:

Efficiency=\frac{work}{heat transfer to power plant}

Heat transfer=\frac{work}{Efficiency\\} \\\\Heat transfer=\frac{800}{0.40}\\\\Heat transfer=2000MW

From First law of thermodynamics:

Rate of heat transfer to river=heat transfer to power plant-work done

Rate of heat transfer to river=2000-800

Rate of heat transfer to river=1200MW

So the actual amount of heat rejected ti the river will be less as there will some heat loss to surrounding and in pipes.

4 0
3 years ago
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