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3 years ago

What do humans breathe

Engineering

2 answers:

shtirl [24]3 years ago

8 0

Water or H2O ;))))

Hope this helps you---

Romashka [77]3 years ago

5 0

Answer:

Inhalation and exhalation are how your body brings in oxygen and gets rid of carbon dioxide. The process gets help from a large dome-shaped muscle under your lungs called the diaphragm. When you breathe in, your diaphragm pulls downward, creating a vacuum that causes a rush of air into your lungs.

Explanation:

xD enjoy the answer hope it helps? :))

You might be interested in

Gear A has a mass of 1 kg and a radius of gyration of 30 mm; gear B has a mass of 4 kg and a radius of gyration of 75 mm; gear C

Kruka [31]

Answer:

(4.5125 * 10^-3 kg.m^2)ω_A^2

Explanation:

solution:

Moments of inertia:

I = mk^2

Gear A: I_A = (1)(0.030 m)^2 = 0.9*10^-3 kg.m^2

Gear B: I_B = (4)(0.075 m)^2 = 22.5*10^-3 kg.m^2

Gear C: I_C = (9)(0.100 m)^2 = 90*10^-3 kg.m^2

Let r_A be the radius of gear A, r_1 the outer radius of gear B, r_2 the inner radius of gear B, and r_C the radius of gear C.

r_A=50 mm

r_1 =100 mm

r_2 =50 mm

r_C=150 mm

At the contact point between gears A and B,

r_1*ω_b = r_A*ω_A

ω_b = r_A/r_1*ω_A

= 0.5ω_A

At the contact point between gear B and C.

At the contact point between gears A and B,

r_C*ω_C = r_2*ω_B

ω_C = r_2/r_C*ω_B

= 0.1667ω_A

kinetic energy T = 1/2*I_A*ω_A^2+1/2*I_B*ω_B^2+1/2*I_C*ω_C^2

=(4.5125 * 10^-3 kg.m^2)ω_A^2

6 0

3 years ago

High-mount stop lamps are typically attached to the exterior of the vehicle using:

I am Lyosha [343]

Answer:

Option A

Explanation:

Nylon retainers are knocking screws that have nylon coating on their thread which prevents them from loosening. It generally has two heads Hex Key an star screw. For high mount fixing, star screw is used as it is less prone to stripping. The nylon insert of a Nylock nuts enters into the screw and prevent it from loosening. It is useful in areas where there is high vibration.

Hence, option A is correct

8 0

3 years ago

When the 2.8-kg bob is given a horizontal speed of 1.5 m/s, it begins to rotate around the horizontal circular path A. The force

Rama09 [41]

Answer:

The speed is the same at 1.5 m/s while

The work done by the force F is 0.4335 J

Explanation:

Here we have angular acceleration α = v²/r

Force = ma = 2.8 × 1.5²/r₁

and ω₁ = v₁/r₁ = ω₂ = v₁/r₂

The distance moved by the force = 600 - 300 = 300 mm = 0.3 m

If the velocity is constant

The speed is 1.5 m/s while the work done is

2.8 × 1.5²1/(effective radius) ×0.3

r₁ = effective radius

2.8*9.81 = 2.8 × 1.5²/r₁

r₁ = 0.229

The work done by the force = 2.8 × 1.5²*1/r₁ *0.3 = 0.4335 J

4 0

3 years ago

Why should a toolpath be verified on the screen of a CAM system prior to creating the program code?

NISA [10]

Answer:

The tool's trajectory in a CAM program refers to the places where the tool will be during the work. It is important to review it before generating the program for the following reasons

1. analyze the machining strategy and identify which one is better for each piece.

2.Avoid the collision of the tool holder with the work piece.

3.Avoid the shock of the tool with the piece.

4. Prevent the collision of the tool with elements that are not displayed on the CAM such as clamping flanges or screws.

5 0

3 years ago

Write a program that will produce a report showing the current and max-imum enrollments for a number of classes. Your applicatio

Andru [333]

Answer:

Check the explanation

Explanation:

CODE

using System;

using System.Collections.Generic;

using System.Text;

using System.Runtime.InteropServices;

namespace listofcourses

{

class Course1

{

public string coursename;

public int courseenrol;

public int maximum;

}

class Courses1

{

public List<Course1> colist = new List<Course1>();

public int coursemaximum;

public int addRecord(string num, int err,int maximum)

{

Course1 c1 = new Course1();

c1.coursename = num;

c1.courseenrol = err;

c1.maximum=maximum;

colist.Add(c1);

coursemaximum = colist.Count;

return 1;

}

class Implement

{

static public Courses1 cos = new Courses1();

static public void printrecord()

{

Console.WriteLine("_______________________________________________________________");

Console.WriteLine("SNo Class Name currentEnroll MaximumEnroll");

Console.WriteLine("_______________________________________________________________");

for (int i = 0; i < cos.coursemaximum; i++)

{

Console.Write("{0, -5}", i + 1);

Console.Write("{0, -19}", cos.colist[i].coursename);

Console.Write("{0, -7}", cos.colist[i].courseenrol);

Console.Write("{0, -7}", cos.colist[i].maximum);

Console.WriteLine();

}

Console.WriteLine("_______________________________________________________________");

}

static public void getRecords()

{

Console.Write("please enter Course Name: ");

string num;

int c1,m1;

num = Console.ReadLine();

Console.Write("Enter current enrollment");

c1= Convert.ToInt32(Console.ReadLine());

Console.Write("Enter maximum enrollment");

m1= Convert.ToInt32(Console.ReadLine());

cos.addRecord(num,c1,m1);

}

static void Main(string[] args)

{

Console.WriteLine("Course Enrollment");

Console.Write("please Enter the number of courses: ");

int ncval = -1;

string xval = Console.ReadLine();

ncval= Convert.ToInt32(xval);

for (int i = 1; i <= ncval; i++)

{

Console.WriteLine("\nEnter " + i.ToString() + " course enrollment\n");

getRecords();

}

printrecord();

char k1 = Console.ReadKey().KeyChar;

}

Kindly check the code output below.

3 0

4 years ago