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k0ka [10]
3 years ago
7

A system contains bonds between particles. Which choice describes the microscopic structures of the energy in this system? There

must be kinetic energy in the bonds due their particles position. There must be potential energy in the bonds due to their particles motion. There must be elastic energy in the bonds due to their particles motion. There must be potential energy in the bonds due to its particles position.
Chemistry
1 answer:
borishaifa [10]3 years ago
8 0

Answer:

The correct answer is: <em>There must be potential energy in the bonds due to its particles position.</em>

Explanation:

Potential energy is a kind of energy which is stored in an object due to its position or configuration. For example, if there is a ball in the fifth floor of a building, it has a determined potential energy which is converted to kinetic energy when the ball fall down. The same is in the case of the chemical bonds: the particles or atoms have potential energy related to their relative positions in the system. In fact,  chemical energy is considered a form of potential energy (stored in chemical bonds).

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A 25.0 ml sample of an hcl solution is titrated with a 0.139 m naoh solution. the equivalence point is reached with 15.4 ml of b
Andreas93 [3]

the balanced equation for the acid base reaction is as follows

NaOH + HCl ---> NaCl + H₂O

stoichiometry of NaOH to HCl is 1:1

the number of NaOH moles is - 0.139 mol/L x 0.0154 L = 0.00214 mol

the number of NaOH moles reacted = number of HCl moles reacted

therefore number of HCl moles reacted = 0.00214 mol

volume of HCl containing 0.00214 mol - 25.0 mL

number of HCl moles in 25.0 mL - 0.00214 mol

therefore number of HCl moles in 1000 mL - 0.00214 mol / 25.0 mL x 1000 mL/L

molarity of HCl is 0.0856 mol/L

concentration of HCl is 0.0856 M


5 0
3 years ago
Read 2 more answers
Zinc Sulfide reacts with oxygen according to the reaction:
zhuklara [117]

The amount in moles of the excess reactant left is 0.5 mole

<h3>Balanced equation</h3>

2ZnS (s) + 3O₂(g) --> 2ZnO (s) + 2SO₂(g)

From the balanced equation,

2 moles of ZnS reacted with 3 moles of O₂

<h3>How to determine the excess reactant</h3>

From the balanced equation,

2 moles of ZnS reacted with 3 moles of O₂

Therefore,

4.2 moles of ZnS will react with =(4.2 × 3) / 2 = 6.3 moles of O₂

From the calculations made above, we can see that only 6.3 moles of O₂ out of 6.8 moles given, is required to react completely with 4.2 moles of ZnS.

Thus, ZnS is the limiting reactant and O₂ is the excess reactant.

<h3> How to determine the mole of the excess reactant remaining</h3>

The excess reactant is O₂. Thus the mole remaining after the reaction can be obtained as illustrated below:

  • Mole of O₂ given = 6.8 moles
  • Mole of O₂ that reacted = 6.3 moles
  • Mole of O₂ remaining =?

Mole of O₂ remaining = (Mole of O₂ given) - (Mole of O₂ that reacted)

Mole of O₂ remaining = 6.8 - 6.3

Mole of O₂ remaining = 0.5 mole

Learn more about stoichiometry:

brainly.com/question/25685654

#SPJ1

6 0
2 years ago
A rigid container of O has a pressure of 340 kPa at a temperature of 713 K. What is the pressure at 273 K?
tia_tia [17]

Answer:

P₂ = 130.18 kPa

Explanation:

In this case, we need to apply the Gay-Lussack's law assuming that the volume of the container remains constant. If that's the case, then:

P₁/T₁ = P₂/T₂   (1)

From here, we can solve for the Pressure at 273 K:

P₂ = P₁ * T₂ / T₁   (2)

Now, all we need to do is replace the given data and solve for P₂:

P₂ = 340 * 273 / 713

<h2>P₂ = 130.18 kPa</h2>

Hope this helps

4 0
3 years ago
Use the ruler to determine the length of this object. Record your answer to the nearest tenth. The object is ____ long.
VLD [36.1K]
The object is 2.7 cm long
7 0
3 years ago
Wolff-kishner reduction (hydrazine, koh, ethylene glycol, 130°c) of the compound shown gave compound
telo118 [61]
The scheme is shown below, the steps involved are as follow,

Step one: Reduction:
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Step two: Epoxidation:
              The double bond present in starting compound when treated with m-CPBA (<span>meta-Chloroperoxybenzoic acid) gives corrsponding epoxide.

Step three: Reduction:
                The epoxide is reduced to alcohol on treatment with Lithium Aluminium Hydride (LiAlH</span>₄)<span> followed by hydrolysis.

Step four: Oxidation:
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8 0
3 years ago
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