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balu736 [363]
3 years ago
5

At what frequency does the driver of the car hear the ambulance’s siren? The velocity of sound in air is 343 m/s.

Physics
1 answer:
Katarina [22]3 years ago
4 0
956.602hz. 

Sorry for the late answer, just came across this.

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Under what condition(vector A + vector B)= (vector A) + (vector B) holds good?
romanna [79]

Answer:

when angle between them is zero degree

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____________ is considered one of the great geniuses and gave us the formula, E=mc2.
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Albert Einstein is your answer.
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Which cell responds most strongly to a stimulus moving perpendicular to its axis?​?
AlladinOne [14]
Complex cells are the types of cells that respond most strongly to a stimulus moving perpendicular to its axis.

This is because like simple cell, a complex cell will respond primarily to oriented edges and rating but it has a specific degree of spatial variance. This means its own receptive field cannot be mapped into fixed excitatory and inhiborty zone. Rather, it will respond to patterns of light in a specific orientation within a large field of reception, regardless of its location. Some of these complex cells respond optimally only to a movement in a certain or specific direction.
5 0
3 years ago
Marc attaches a falling 500-kg object with a rope through a pulley to a paddle wheel shaft. He places the system in a well-insul
Klio2033 [76]

Answer:

4.68227 °C

Explanation:

m_o = Mass of object = 500 kg

m_w = Mass of water = 25 kg

c = Specific heat of water at 20°C = 4186 J/kg°C

h = Height from which the object falls = 100 m

g = Acceleration due to gravity = 9.8 m/s²

The potential energy and heat will balance each other

PE=Q\\\Rightarrowmc m_ogh=m_oc\Delta T\\\Rightarrow \Delta T=\frac{m_ogh}{m_oc}\\\Rightarrow \Delta T=\frac{500\times 9.8\times 100}{25\times 4186}\\\Rightarrow \Delta=4.68227\ ^{\circ}C

The temperature change in the water is 4.68227 °C

5 0
3 years ago
Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of 150
Sever21 [200]

Answer:2.89\approx 2.9^{\circ}C/s

Explanation:

Given

Power\left ( P\right )=150 MW

mass of core\left ( m\right )=1.60\times 10^5 kg

Average specific heat \left ( C\right )=0.3349 KJ/kg^{\circ}C

And rate of increase of temperature =\frac{\mathrm{d}T}{\mathrm{d} t}

Now

P=mc\frac{\mathrm{d}T}{\mathrm{d} t}

150\times 10^6=1.60\times 10^5\times 0.3349\times \frac{\mathrm{d}T}{\mathrm{d} t}

Thus \frac{\mathrm{d}T}{\mathrm{d} t}=[tex]\frac{1.60\times 10^5\times 0.3349}{150\times 10^6}

\frac{\mathrm{d}T}{\mathrm{d} t}=2.89\approx 2.9^{\circ}C/s

6 0
4 years ago
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