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2 years ago

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I need the answer so much

1 answer:

Mariulka [41]2 years ago

4 0

I don't know sorry just google it

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Convert 30 g of Na O to liters.

Bess [88]

Answer:

0.03 liters

Explanation:

1g = 0.001L

30 * 0.001 = 0.03L

Best of Luck!

5 0

3 years ago

Read 2 more answers

Name 5 affects of weathering and erosion

nadezda [96]

Answer Water, wind, and ice can also move pieces of rock or land to new places. The wearing away of a surface of rock or soil is called weathering. ... Weathering and erosion can cause changes to the shape, size, and texture of different landforms (such as mountains, riverbeds, beaches, etc).:

Explanation:

3 0

2 years ago

Why do light-fur mice survive less often on dark rocks, compared to dark- figure mice?

mariarad [96]

Answer:

Light fur mice can be easily spotted by predators among the dark rocks

3 0

3 years ago

Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions.

Norma-Jean [14]

$2 KHP(aq) + Ba(OH)_{2}(aq) ---> KP_{2}Ba (aq) + 2 H_{2}O (l)$ \

Moles of $Ba(OH)_{2}$ = $0.483 \frac{mol}{L} * 28.5 mL *\frac{1 L}{1000mL} = 0.0138 mol Ba(OH)_{2}$

Mass of KHP = $0.0138 mol Ba(OH)_{2} * \frac{2 mol KHP}{1 mol Ba(OH)_{2}} * \frac{204.22 g KHP}{1mol KHP}$

= 5.64 g KHP

6 0

3 years ago

Read 2 more answers

How many seconds does it take to deposit 0.94 g of Ni on a decorative drawer handle when 14.9 A is passed through a Ni(NO3)2 sol

Goshia [24]

Answer:

Time take to deposit Ni is 259.02 sec.

Explanation:

Given:

Current $I = 14.9$ A

Faraday constant $= 96485$ $\frac{C}{mole}$

Molar mass of Ni $= 58.69$ $\frac{g}{mole}$

Mass of Ni $= 0.94$ g

First find the no. moles in Ni solution,

Moles of Ni $= \frac{0.94}{58.69}$

$= 0.02$ mol

From the below reaction,

$Ni^{2+} + 2e$ ⇆ $Ni_{(s)}$

Above reaction shows "1 mol of $Ni^{2+}$ requires 2 mol of electron to form 1 mol of $Ni_{(s)}$ "

So for finding charge flow in this reaction we write,

$=$ $0.02 \times \frac{2 }{1 } \times 96485 \frac{C}{mol}$

Charge flow $= 3859.4$ C

For finding time of reaction,

$I = \frac{q}{t}$

Where $q =$ charge flow

$t = \frac{q}{I}$

$t = \frac{3859.4}{14.9}$

$t = 259.02$ sec

Therefore, time take to deposit Ni is 259.02 sec.

3 0

2 years ago