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Usimov [2.4K]
3 years ago
5

In a chemical reaction,_______________are the substances present after the reaction.

Chemistry
2 answers:
dsp733 years ago
8 0

Answer:

In a chemical reaction, <u>products</u> are the substances present after the reaction

siniylev [52]3 years ago
7 0

The answer is products

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Find the percent ionization of a 0.337 m hf solution. the ka for hf is 3.5 x 10-4. 1.1 % 1.2 x 10-2 % 3.2 % 3.5 x 10-2 % 4.7 %
Ugo [173]

To determine the percent ionization of the acid given, we make use of the acid equilibrium constant (Ka) given. It is the ration of the equilibrium concentrations of the dissociated ions and the acid. The dissociation reaction of the HF acid would be as follows:<span>

HF = H+ + F-

The acid equilibrum constant would be expressed as follows:

Ka = [H+][F-] / [HF] = 3.5 x 10-4

To determine the equilibrium concentrations we use the ICE table,
         HF             H+              F-
I      0.337           0                 0
C      -x              +x               +x
---------------------------------------------
E    0.337-x        x                   x 

3.5 x 10-4 = [H+][F-] / [HF] 
3.5 x 10-4 = [x][x] / [0.337-x] </span>

Solving for x,

x = 0.01069 = [H+] = [F-]

percent ionization = 0.01069 / 0.337 x 100  = 3.17%

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3 years ago
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Chemistry: how does temperature relate to kinetic energy? pls answer in a short and easy way :D
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The hotter it is, the faster the atoms in something are moving.

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2 years ago
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Many types of scientific equipment are used to perform different functions in the science lab. Which of the following combinatio
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I guess B is the right one......
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Palmitic acid C16H32O2 is a dietary fat found in beef and butter. The caloric content of palmitic acid is typical of fats in gen
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C16H32O2(aq) --> 16CO2(g) + 16H2O(l) ... said its wrong though? 
<span>This is because you haven't added any oxygen needed for the combustion, so your equation does'nt balance. Also a solution in water [aq] doesn't burn! </span>
<span>Try </span><span>C16H32O2(s) + 23O2(g) --> 16CO2(g) + 16H2O(l) 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
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3 years ago
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Write the ground state electron configuration of zn using the noble-gas shorthand notation.
V125BC [204]
Atomic Number of Zinc is 30, means it contains 30 electrons. So, its electronic configuration is as follow,

                                    1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰
As,
          1s², 2s², 2p⁶, 3s², 3p⁶  =  Argon
So,
Electronic configuration of Zinc in shorthand notation is as follow,

                                     [Ar] 4s², 3d¹⁰
8 0
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