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Nadya [2.5K]
3 years ago
8

Does iron rust? I need to have this question answered for my science class

Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
4 0

When iron is exposed to oxygen and moisture for a long period of time,then rusting of the iron occurs. Now when iron reacts with oxygen and water then iron oxide is formed. Iron oxide(Ferric oxide) is the chemical name for rust.  Rust constitutes of hydrated Ferric oxide. Only iron or alloys that contain iron can rust. Water acts as a catalyst in the rusting process of iron.

First oxidation of the ferrous ion takes place. The ferrous ion gets converted to ferric ions. This is a redox reaction.

4 Fe2+ + O2 → 4 Fe3+ + 2 O2−

where Fe2+ is the ferrous ions and Fe3+ are the ferric ions.

Then the ferric ions react with the water molecules to form ferric hydroxide or rust.

Fe3+ + 3  H2O ⇌ Fe(OH)3 + 3  H+

where Fe(OH)3 is ferric hydroxide also called as rust.

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when an electron gets closer to the nucleus does the attraction or repulsion grow weaker or stronger?
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Answer:

Weaker

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How would the pH value of an aqueous solution change, when the hydronium ion concentration is increased by a factor of 10?
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Answer:

Increasing H⁺ by 10x => pH decreases by 1 unit

Explanation:

In general, adding H⁺ ions to any aqueous solution ALWAYS causes pH values to fall ( decrease ). Just as adding OH⁻ ions to an aqueous solution causes pH values to rise ( increase ).

Here's a simple calculation demonstrating this...

Given 0.01M HCl(aq) => 0.01M H⁺(aq) + Cl⁻(aq) => pH = -log(0.01) = 2.00

Increase [H⁺] by 10x => 0.10M H⁺(aq) => pH = -log[H⁺] = -log(0.10) = 1.00

Solution with higher H⁺ concentration shows <u>pH decreasing by 1 unit.</u>

______________________________________________________-

Just to support the above statement about adding OH⁻ ions showing an increase in pH values, the following is also provided FYI ..

Given 0.01M NaOH(aq) => 0.01M OH⁻(aq) + Na⁺(aq) => pOH = -log(0.01) = 2.00 => pH = 14 - pOH = 14 - 2 = 12

Increase [OH⁻] by 10x => 0.10M OH⁻(aq) => pOH = -log[OH⁻] = -log(0.10) = 1.00 => pH = 14 - pOH = 14 - 1 = 13

Increasing [OH⁻] by 10x => <u>increasing pH by 1 unit. </u>

Solution with higher H⁺ concentration shows pH decreasing by 1 unit.

______________________________________________________

Remember, for <u>any</u> aqueous solution ...

=> Adding H⁺   => always decreases pH

=> Adding OH⁻ => always increases pH

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