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Tom [10]
3 years ago
7

The rusting of iron is due to its reaction with oxygen. An iron nail weighing 8.531 g was left outdoors for a period of one year

. After the one year it was found to have a mass of 12.197 g. How many grams of oxygen did the nail react with
Chemistry
1 answer:
Annette [7]3 years ago
4 0

Answer:

m(O₂) = 3.666 g

Explanation:

The rusting of iron is due to its reaction with oxygen. The balanced equation is:

4 Fe + 3 O₂ → 2 Fe₂O₃

According to Lavoisier's law of conservation of mass, the sum of the masses of the reactants is equal to the sum of the masses of the products.

m(reactants) = m(products)

m(Fe) + m(O₂) = m(Fe₂O₃)

8.531 g + m(O₂) = 12.197 g

m(O₂) = 3.666 g

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Why does the dilution equation, M 1 V 1 = M 2 V 2, work?
valentina_108 [34]

Answer:

d) The dilution equation works because the number of moles remains the same.

Explanation:

Let’s say that you have 1 mol of a solute in I L of solution. The concentration is 1 mol·L⁻¹. and <em>M</em>₁<em>V</em>₁ = 1 mol.

Now, you dilute the solution to a volume of 2 L. You still have 1 mol of solute, but in 2 L of solution. The new concentration is 0.5 mol·L⁻¹.

The volume has doubled, but the volume has halved, and <em>M</em>₂<em>V</em>₂ = 1 mol.

b) <em>Wrong</em>. The molar concentration changes on dilution.

c) <em>Wrong</em>. The volume changes on dilution.

a) <em>Wrong</em>, although technically correct, because if the moles don’t change, the mass doesn’t change either. However, the formula <em>M</em>₁<em>V</em>₁ has units mol·L⁻¹ × L = mol. Thus, in the formula, it is moles that are constant.

6 0
4 years ago
Read 2 more answers
How many moles of silver oxide (l) are needed to produce 4 moles of silver?
ozzi

The number of moles of silver oxide (I) needed to produce 4 moles of silver is 2 moles

<h3>Stoichiometry </h3>

From the question, we are to determine the number of moles of silver oxide (I) needed to produce 4 moles of silver

First, we will write the balaced chemical equation for the decomposition of silver oxide (I)

2Ag₂O(s) → 4Ag(s) + O₂(g)

This means, 2 moles of silver oxide (I) [Ag₂O] decomposes to give 4 moles of <u>silver </u>and 1 mole of oxygen gas.

From the <em>balanced chemical equation</em>, it is easy to deduce the number of moles of silver oxide (I) that would give 4 moles of silver.

Hence, the number of moles of silver oxide (I) needed to produce 4 moles of silver is 2 moles

Learn more on Stoichiometry here: brainly.com/question/18834543

7 0
3 years ago
3. Identify the spectator ion(s) in the following reaction.
Arlecino [84]
Answer is e ht and ct
3 0
3 years ago
Nitrogen has an atomic mass of about 14 amu and an atomic number of 7. how many neutrons does nitrogen have?
Finger [1]
Nitrogen has 7 neutrons.
3 0
4 years ago
Read 2 more answers
What is the percent yield of NaCl if 31.0 g of CuCl2 reacts with excess NaNO3 to produce 21.2 g of NaCl?
Harrizon [31]
First you need to find the balanced chemical formula.
CuCl₂+2NaNO₃→2NaCl+Cu(NO₃)₂

Then you can find out how much NaCl 31.0g of CuCl₂ should produce using stoichiometry.  Divide 31.0g by the molar mass of CuCl₂ (134.446g/mol) to get 0.2306mol CuCl₂.  Than multiply 0.2306mol CuCl₂ by 2 to get 0.4612mol NaCl.  Than multiply 0.4612mol by the molar mass of NaCl (58.45g/mol) to get 26.95g of NaCl.
that means that 100% yield would give you 26.95g of NaCl so to find percent yield divide 21.2 by 26.95 to get 0.7867 which is 78.7% yield

Therefore the answer is 78.7% yield.
I hope this helps.  Let me know if anything is unclear
3 0
3 years ago
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