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Nataliya [291]
3 years ago
13

How many moles of propane (C3H8) are in my grill’s tank if the pressure is 7 atm at a volume of 15L and a temperature of 23˚C?

Chemistry
1 answer:
Nadya [2.5K]3 years ago
7 0

In this situation, we can use the ideal gas equation which is PV = nRT

P = Pressure (atm)

V = Volume (L)

n = moles (mol)

R = constant (0.08206 atm-l/mol-K)

T = Temperature (K) ---> C + 273.15 = K

PV = nRT

n = PV/RT

  = (7atm)(15L) / (0.08206 atm-l/mol-K)(23 + 273.15)

  = 4.32 mol

Hope that helped!!!

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Hello.

In this case, taking into account that HCl has one molecule of hydrogen per mole of compound which weights 36.45 g/mol, we compute the number of molecules of hydrogen in hydrochloric acid by considering the given mass and the Avogadro's number:

molec_{\ H}=3.65gHCl*\frac{1molHCl}{36.45gHCl} *\frac{1molH}{1molHCl}*\frac{6.022x10^{23}molec_\ H}{1molH}  =6.03x10^{22}molec

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molec_{\ H}=180gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}molec_\ H}{1molH}  =1.20x10^{25}molec

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