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Citrus2011 [14]
3 years ago
9

Later, while taking your groceries back to the car, you accidentally let go of your cart. It rolls straight down a grassy slope

at a constant speed of 10 m/s. What is the net force on the cart during this motion
Physics
1 answer:
VladimirAG [237]3 years ago
6 0

Car is moving on the glassy slope with constant speed

Now we know that

a = \frac{dv}{dt}

so acceleration is rate of change in velocity

as we know that velocity is constant here so acceleration is zero

so here

a = 0

now as we know by Newton's II law

F = ma

since a = 0

F = 0

so net force will be ZERO on it during this motion

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An electron enters a region with a speed of 5×10^6m/s and is slowed down at the rate of 1.25×10^-4m/s². How far does the electro
Mashutka [201]

1) The distance travelled by the electron is 1\cdot 10^{17} m

2) The time taken is 4.0\cdot 10^{10}s

Explanation:

1)

The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance travelled

For the electron in this problem,

u=5\cdot 10^6 m/s is the initial velocity

v = 0 is the final velocity (it comes to a stop)

a=-1.25\cdot 10^{-4} m/s^2 is the acceleration

Solving for s, we find the distance travelled:

s=\frac{v^2-u^2}{2a}=\frac{0-(5\cdot 10^6)^2}{2(-1.25\cdot 10^{-4})}=1\cdot 10^{17} m

2)

The total time taken for the electron in its motion can also be found by using another suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

Here we have

u=5\cdot 10^6 m/s

v = 0

a=-1.25\cdot 10^{-4} m/s^2

And solving for t, we find the time taken:

t=\frac{v-u}{a}=\frac{0-5\cdot 10^6}{-1.25\cdot 10^{-4}}=4.0\cdot 10^{10}s

Learn more about accelerated motion:

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brainly.com/question/2562700

#LearnwithBrainly

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