The methane molecule undergoes oxidation and the carbon is oxidized to carbon dioxide and hydrogen to water.
In this reaction there is cleavage of four C-H bonds and two O=O bonds
there will be formation of two C=O bonds and four O-H bonds.
Overall due to more bond cleavage energy there will be evolution of energy. thus combustion is an exothermic reaction.
Answer:
The Ideal gas law
Explanation:
From the given question, we have:
V

where each variable has its usual meaning.
Thus,
V = 
where R is the ideal gas constant
cross multiply to have;
PV = nRT
This implies that the volume of the gas is directly proportional to the number of moles of the gas.
Therefore, the law can be used to determine the relationship between the volume and number of moles is the ideal gas law.
There are 4 atoms of sodium in the formula of sodium sulfite.
<h3 /><h3>Number of atoms at sodium</h3>
There are 4 atoms of sodium in the formula of sodium sulfite because 4 digit is placed before sodium which shows the number of sodium atom present in the molecule while on the other hand, 2 is placed in front of sulfur which tells us that 2 atoms of sulfur is used in the making of sodium sulfite.
<h3>Reasons of war</h3>
In this excerpt, Paine is attempting to convince the readers that we have righteous reasons to justify supporting the war. We should participate and take part in the war in order to defend ourselves and our country but avoid offensive war to gain financial benefits.
Learn more about war here: brainly.com/question/1174232
Learn more: brainly.com/question/26123703
Answer:
The dilution factor of protein in tube # 4 is 125. Molar concentration is 0.0088 M protein
Explanation:
The dilution factor indicates how many times is more concentrated a main solution in relationship with a diluted solution. In this case, the main solution is in tube #1. For calculating the dilution factor and molar concentration in tube #4 we need the main solution concentration which comes from next equation:
Initial volume * initial concentration = final volume * final concentration
0.5 mL * 10M = 5mL * final concentration
1.1 M = final concentration = main solution concentration
Applying the same equation for remain tubes we have 0.22 M for tube #2, 0.044 M for tube # 4 and 0.0088 for tube # 4.
Dilution factor = Main solution concentration/tube 4 concentration
Dilution factor = 1.1/0.0088 = 125
I hope my answer helps you