The temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.
<h3>What is Combined gas law?</h3>
Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.
It is expressed as;
P₁V₁/T₁ = P₂V₂/T₂
Given the data in the question;
- Initial volume V₁ = 14.5L
- Initial pressure P₁ = 0.980atm
- Initial temperature T₁ = 20.0°C = 293.15K
- Final pressure P₂ = 740.mmHg = 0.973684atm
We substitute our given values into the expression above.
P₁V₁/T₁ = P₂V₂/T₂
( 0.980atm × 14.5L )/293.15K = ( 0.973684atm × 14.3L )/T₂
14.21Latm / 293.15K = 13.92368Latm / T₂
14.21Latm × T₂ = 13.92368Latm × 293.15K
14.21Latm × T₂ = 4081.72679LatmK
T₂ = 4081.72679LatmK / 14.21Latm
T₂ = 287.24K
T₂ = 14.09°C
Therefore, the temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.
Learn more about the combined gas law here: brainly.com/question/25944795
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Answer : The grams of carbon monoxide needed are 148.89 g
Solution : Given,
Mass of iron, Fe = 198.5 g
Molar mass of iron, Fe = 56 g/mole
Molar mass of carbon monoxide, CO = 28 g/mole
First we have to calculate the moles of iron, Fe.
The balanced chemical reaction is,
From the balanced reaction, we conclude that
2 moles of iron produces from the 3 moles of carbon monoxide
3.545 moles of iron produces from the 
moles of carbon monoxide
Now we have to calculate the mass of carbon monoxide, CO.
Therefore, the grams of carbon monoxide needed are 148.89 g
I want to say 59 atomic mass units<span> is beta decay, but I'm just guessing from previous Chem. class.</span>
