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3 years ago

Why do you think they stilk proruxe bright flowers to attract bees?

Chemistry

2 answers:

Reil [10]3 years ago

5 0

A ) flowers need honey that bees provide in order to grow

Ede4ka [16]3 years ago

4 0

Answer:

Explanation:

In order for plants to entice pollinators, they must first offer their favorite foods: nectar and protein. Since most pollinators fly, the colors of a flower must attract them; therefore, the brighter the flower, the more likely it will be visited. ... For instance, bees are attracted to bright blue and violet colors.

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A standard 10.00 g mass is weighed on an analytical balance 100 times. The average and standard deviation obtained gives 10.12 ±

Mekhanik [1.2K]

Answer:

There was an improvement in accuracy. There was no change in precision.

Explanation:

<em>The average mass after recalibration is closer to the mass of the standard, </em>so the recalibration improved the accuracy<em> </em>(the measurement is closer to an accepted 'true' value).

The standard deviation did not change, so the precision (or how disperse the measurements are) was not affected.

5 0

3 years ago

In 1909 Fritz Haber discovered the workable conditions under which nitrogen, N2(g), and hydrogen, H2(g), would combine using to

labwork [276]

Answer : 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

Solution : Given,

Mass of $NH_3$ = 100 g

Molar mass of $NH_3$ = 27 g/mole

Molar mass of $N_2$ = 28 g/mole

First we have to calculate moles of $NH_3$ .

$\text{ Moles of }NH_3=\frac{\text{ Mass of }NH_3}{\text{ Molar mass of }NH_3}= \frac{100g}{27g/mole}=3.7moles$

The given balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

From the given reaction, we conclude that

2 moles of $NH_3$ produced from 1 mole of $N_2$

3.7 moles of $NH_3$ produced from $\frac{1mole}{2mole}\times 3.7mole=1.85moles$ of $N_2$

Now we have to calculate the mass of $N_2$ .

Mass of $N_2$ = Moles of $N_2$ × Molar mass of $N_2$

Mass of $N_2$ = 1.85 mole × 28 g/mole = 51.8 g

Therefore, 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

5 0

3 years ago

Mammals use their lungs to provide oxygen for themselves from the air. Fish spend a majority of their time in the water, and ins

Elenna [48]

B of course is the answer

7 0

2 years ago

Read 2 more answers

a 6.7 volume of air, initially at 23 degrees celsius and .98 atm, is compressed to 2.7 L while heated to 125 degrees celsius. Wh

Annette [7]

Data:

V1 = 6.7 liter
T1 = 23° = 23 + 273.15 K = 300.15 K
P1 = 0.98 atm

V2 = 2.7 liter
T2 = 125° = 125 + 273.15 K = 398.15 K
P2 = ?

Formula:

Combined law of ideal gases: P1 V1 / T1 = P2 V2 / T2

=> P2 = P1 V1 T2 / (T1 V2)

P2 = 0.98 atm * 6.7 liter * 398.15 K / (300.15K * 2.7 liter)

P2 = 3.22 atm

6 0

3 years ago

A 0.10 M solution of Na2HPO4 could be made a buffer solution with all of the following EXCEPT ________.NaH2PO4K3PO4Na3PO4H3PO4

Kipish [7]

The answer is: H₃PO₄.

A phosphoric acid is three protic acid, which means that in water release tree protons.

Phosphoric acid ionizes in three steps in water.

First step: H₃PO₄(aq) ⇄ H₂PO₄⁻(aq) + H⁺(aq).

Second step: H₂PO₄⁻(aq)⇄ HPO₄²⁻(aq) + H⁺(aq).

Third step: HPO₄²⁻(aq) ⇄ PO₄³⁻(aq) + H⁺(aq).

Species that are present: H₃PO₄, H₂PO₄⁻, HPO₄²⁻, PO₄³⁻ and H⁺.

A buffer can be defined as a substance that prevents the pH of a solution from changing by either releasing or absorbing H⁺ in a solution.

Buffer is a solution that can resist pH change upon the addition of an acidic or basic components and it is able to neutralize small amounts of added acid or base, pH of the solution is relatively stable.

7 0

3 years ago