Question

__________ an ideal cross sectional velocity distribution taken in a channel that is more than 10 diameters downstream of an obstruction the highest velocity should be lcoated

Answer 1

Answer: The maximum velocity of fluid flowing in a circular channel occurs at the centre of the channel.

Explanation: starting from the material balance equation and going through Newton's law of viscosity.

The velocity profile of a circular channel is

V(r) = Vmax(1 - (r/R)^2))

V(r) is velocity at any point in the circular channel along the radial direction starting from r=0 at the centre and r=R at the internal side of the circular channel.

So, the maximum obtainable from that distribution is at the centre where r=0 and V(r) = Vmax.