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frosja888 [35]
2 years ago
14

Which metal gets coated during electroplating? A. The metal with electrons flowing from it

Chemistry
1 answer:
DochEvi [55]2 years ago
8 0

Answer: The metal that is the cathode (B)

Explanation:

because i am so smart STAN BLACKPINK! listen to HOW YOU LIKE THAT!

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17 p<br> 18 n<br> What is the atomic number of this element?
Verdich [7]

Answer:

Chlorine

Explanation:

The P usually stands for Protons, and that is usually the element number. (chlorine is 17) N is for neutron

6 0
3 years ago
Which condition must be met in order for an equation to be balanced?
olga55 [171]

Answer:

The elements in the reactants are the same as the elements in the products.

Explanation:

You can't have more or less elements or atoms, but you also can't just have the same number of atoms because then it could be different elements, which can't happen.

5 0
3 years ago
Read 2 more answers
Convert 16.8 L of nitrogen monoxide gas at STP to grams .
german

Answer:

See explanation

Explanation:

1 mole of a gas occupies 22.4 L

x moles occupies 16.8 L

x = 1 mole *  16.8 L/22.4 L

x = 0.75 moles

number of moles = mass/molar mass

mass =  number of moles  * molar mass

mass =  0.75 moles * 30.01 g/mol = 22.5075 g = 2.25 * 10^1 g

the coefficient of the scientific notation answer = 2.25

the exponent of the scientific notation answer = 1

significant figures are there in the answer = 6

the right most significant figure in the answer = 3

2.

number of moles = 12.5g/38g/mol = 0.3289 moles

1 mole occupies 22.4 L

0.3289 moles occupies 0.3289 moles * 22.4 L/1 mole

= 7.36736 L = 7.36736 * 10^0 L= 7.37 * 10^0 L

the coefficient of the scientific notation answer =7.37

the exponent of the scientific notation answer = 0

significant figures are there in the answer = 6

the right most significant figure in the answer= 3

8 0
3 years ago
Dehydrohalogenation of 1-chloro-1-methylcyclopropane affords two alkenes (A and B) as products.
UNO [17]

Explanation:

Dehydrohalogenation reactions occurs as elimination reactions through the following mechanism:

Step 1: A strong base(usually KOH) removes a slightly acidic hydrogen proton from the alkyl halide.

Step 2: The electrons from the broken hydrogen‐carbon bond are attracted toward the slightly positive carbon (carbocation) atom attached to the chlorine atom. As these electrons approach the second carbon, the halogen atom breaks free.

However, elimination will be slower in the exit of Hydrogen atom at the C2 and C3 because of the steric hindrance by the methyl group.

Elimination of the hydrogen from the methyl group is easier.

Thus, the major product will A

4 0
3 years ago
According to markovnikov's rule of the electrophilic addition to an alkene, the electrophile, usually a proton, is more likely t
stealth61 [152]

According to markovnikov's rule of the electrophilic addition to an alkene, the electrophile, usually a proton, is more likely to add to the less-substituted carbon in a double bond.

With additional substituents present in this configuration, the intermediate carbocation is stabilised by being located on the more-substituted carbon.

The nucleophile will then end up in a double bond on the more-substituted carbon in a reaction that follows Markovnikov's rule.The outcome of some addition reactions is described by Markovnikov's rule or Markownikoff's rule in organic chemistry. Vladimir Markovnikov, a Russian scientist, created the rule in 1870.

To learn more about Markovnikov's rule

brainly.com/question/14529644

#SPJ4

8 0
2 years ago
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