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3 years ago

1. During an oceanic plate convergence, the plate will sink

Chemistry

2 answers:

Novosadov [1.4K]3 years ago

4 0

Answer:

A good answer should contain the following:

1. denser

2. subduction

3. hot spots

4. earthquakes

5. An underwater hot-spot volcano occasionally erupts, and the lava solidifies into an island. However, the plate that lies above the hot spot continues to move due to slab pull and ridge push, so the stationary volcano will be in a different location when it erupts again. This forms a new island, and the process may continue.

Explanation:

This is correct on penn foster

Lorico [155]3 years ago

3 0

Answer:

1. denser

2. subduction

3. divergence

4. hot spots

5. earthquakes

6. An underwater hot-spot volcano occasionally erupts, and the lava solidifies into an island. However, the plate that lies above the hot spot continues to move due to slab pull and ridge push, so the stationary volcano will be in a different location when it erupts again. This forms a new island, and the process may continue.

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1. The solubility of lead(II) chloride at some high temperature is 3.1 x 10-2 M. Find the Ksp of PbCl2 at this temperature.

solniwko [45]

Answer:

1) The solubility product of the lead(II) chloride is $1.2\times 10^{-4}$ .

2) The solubility of the aluminium hydroxide is $1.6\times 10^{-10} M$ .

3)The given statement is false.

Explanation:

Solubility of lead chloride = $S=3.1\times 10^-2M$

$PbCl_2(aq)\rightleftharpoons Pb^{2+}(aq)+2Cl^-(aq)$

S 2S

The solubility product of the lead(II) chloride = $K_{sp}$

$K_{sp}=[Pb^{2+}][Cl^-]^2$

$K_{sp}=S\times (2S)^2=4S^3=4\times (3.1\times 10^{-2})^3=1.2\times 10^{-4}$

The solubility product of the lead(II) chloride is $1.2\times 10^{-4}$ .

Concentration of aluminium nitrate = 0.000010 M

Concentration of aluminum ion = $1\timed 0.000010 M=0.000010 M$

Solubility of aluminium hydroxide in aluminum nitrate solution = $S$

$Al(OH)_3(aq)\rightleftharpoons Al^{3+}(aq)+3OH^-(aq)$

S 3S

The solubility product of the aluminium nitrate = $K_{sp}=1.0\times 10^{-33}$

$K_{sp}=[Al^{3+}][OH^-]^3$

$1.0\times 10^{-33}=(0.000010+S)\times (3S)^3$

$S=1.6\times 10^{-10} M$

The solubility of the aluminium hydroxide is $1.6\times 10^{-10} M$ .

$Molarity=\frac{Moles}{Volume (L)}$

Mass of NaCl= 3.5 mg = 0.0035 g

1 mg = 0.001 g

Moles of NaCl = $\frac{0.0035 g}{58.5 g/mol}=6.0\times 10^{-5} mol$

Volume of the solution = 0.250 L

$[NaCl]=\frac{6.0\times 10^{-5} mol}{0.250 L}=0.00024 M$

1 mole of NaCl gives 1 mole of sodium ion and 1 mole of chloride ions.

$[Cl^-]=[NaCl]=0.00024 M$

Moles of lead (II) nitrate = n

Volume of the solution = 0.250 L

Molarity lead(II) nitrate = 0.12 M

$n=0.12 M]\times 0.250 L=0.030 mol$

1 mole of lead nitrate gives 1 mole of lead (II) ion and 2 moles of nitrate ions.

$[Pb^{2+}]=[Pb(NO_2)_3]=0.030 M$

$PbCl_2(aq)\rightleftharpoons Pb^{2+}(aq)+2Cl^-(aq)$

Solubility of lead(II) chloride = $K_{sp}=1.2\times 10^{-4}$

Ionic product of the lead chloride in solution :

$Q_i=[Pb^{2+}][Cl^-]^2=0.030 M\times (0.00024 M)^2=1.7\times 10^{-9}$

$Q_i$ ( no precipitation)

The given statement is false.

3 0

3 years ago

A car averages 27.5 miles per gallon

FrozenT [24]

How much is each gallon or how far are you going is the question you should be asking

6 0

3 years ago

Which of the following statements is false? Check all that apply. Gases are far more compressible than liquids The volume occupi

Sergio039 [100]

Answer:

The false statement is: 3. Because liquid water and liquid carbon tetrachloride do not mix, neither do their vapors

Explanation:

Gas is a state of matter, that has less density than liquids and solids. The gaseous particles have low intermolecular forces and thus they can move freely.

It is a very compressible fluid that has no fixed shape. Gas occupies the whole container in which it is stored, thus taking the shape of the container. Therefore, the volume of the gas is equal to the volume of the container.

Polar liquid like water (H₂O) and nonpolar liquid like carbon tetrachloride, are immiscible. However, in the gaseous state, their vapors form a homogeneous mixture.

5 0

3 years ago

What is the concentration in % (v/v) of 175 mL of isopropyl alcohol that is

Vitek1552 [10]

Answer:

40/220 ×100=18.6 is all I got I know that by heart so um yea

Explanation:

3 0

2 years ago

At standard pressure, ammonia melts at 195 K and boils at 240 K. If a sample of ammonia at standard pressure is cooled from 200

Svetradugi [14.3K]

Answer:

I) the heat capacity of ammonia(s)

II) the heat capacity of ammonia(ℓ)

IV) the enthalpy of fusion of ammonia

Explanation:

Initially, ammonia at 200 K is liquid. To calculate the change of enthalpy from 200 K to 195 K (melting point) we need to know the heat capacity of ammonia(ℓ).

At 195, ammonia is in the transition from liquid to solid (solidification). To calculate the change of enthalpy in that process we need to know the enthalpy of solidification of ammonia, which has the same value but opposite sign to the enthalpy of fusion of ammonia.

From 195 K to 0 K, ammonia is solid. To calculate the change of enthalpy in that process we need to know the heat capacity of ammonia(s).

7 0

3 years ago