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Oksanka [162]
3 years ago
7

Matching questions 1. velocity 2. speed 3. gravity 4. deceleration 5. newton A acceleration in the opposite direction as the vel

ocity of the object; results in speed decreasing B the rate at which an object changes position when traveling in a certain direction, expressed as a rate: distance divided by time + direction C force of attraction between all masses in the universe D the unit of force in the metric system; it is a unit derived from mass and acceleration (speed over time in a direction) E the rate at which an object changes position; distance divided by time
Physics
1 answer:
Ugo [173]3 years ago
3 0

Answer:

1. Velocity match with B

2. Speed watch with E

3. Gravity match with C

4. Deceleration match with A

5. Newton match with D

Explanation:

1.)

  Velocity is defined as the time rate of change of displacement. It is a vector quantity. So it has certain direction as mention in option B. So B is the correct matching.

                         v  = Δd/Δt

2.)

   Speed is defined as the time rate of change of distance. It is a scalar quantity. It is same as velocity but only difference is that velocity has magnitude as well as direction but speed has only magnitude. As in option E, direction not mentioned. So E is the correct matching.

3.)

  Gravity is the force of attraction between any two objects, two masses. It is not only the force between body and the Earth but it is the force that exist between any two bodies in the universe. C is the correct matching.

4.)

  Deceleration is actually the acceleration but in the opposite direction. It is also called negative acceleration. When the velocity of the object increasing it is acceleration and when velocity decreasing it is called deceleration. It is always opposite direction to velocity. So A is the correct matching.

5.)

   Newton is the name of the scientist. Also it is the unit of force in metric system. Here newton means unit of force because n of newton in small letter. From Newton's second law of motion

                              F = ma

                                 = (kg)(m/s²)

                                 = N

Thus,

                                N = kgms⁻²

Option D is correct matching.

   

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<h3>How to calculate  thrust provided by the rocket engines is 10 kN (10 000 N).?</h3>

a)There is this impulse-momentum change equation.

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We consider everything exits happen along a straight line, and gravitation does not participate.

So, the increase of momentum is F×t = 10000 N × 60 seconds = 600000 N*s = 600000 (kg*m)*s/s^2 = 600000 kg*m/s.

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To learn more about Impulse-momentum, refer

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6 0
4 years ago
How much force is needed to accelerate a 2500 kg car at a rate of 3.5 m/s^2?
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F = ma  

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m = mass of the car = 2,500 kg  

a = acceleration of the car = 3.5 m/s²  

F = (2,500 kg)(3.5 m/s²)  

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4 0
4 years ago
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