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Shtirlitz [24]
3 years ago
14

A(n) __________ is a recording of a motion picture, or television program for playing through a television.

Physics
2 answers:
Soloha48 [4]3 years ago
4 0

Answer:

Video

Explanation:

Hope this helps! If it does, drop a 5 star!

lord [1]3 years ago
3 0

Answer:

b video

Explanation:

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the net force on a vehicle is accelerating at a rate of 1.5 milliseconds is 1800 Newtons. What is the mass of the vehicles neare
Goryan [66]

Answer:

The mass is 1200 kilograms

Explanation:

Because Force is equal to mass times acceleration (F=m×a)

F=m×a

1800N=?×1.5

1800÷1.5=1200

1800N=1200Kg×1.5

7 0
3 years ago
The blank tells how many and the blank tells of what
motikmotik

Answer:  and a theme

Explanation:

3 0
3 years ago
Read 2 more answers
A gas has four moles under a pressure of 5.4 atm has a volume of 120 L. What is the
Sunny_sXe [5.5K]

Answer:

1973. K

Explanation:

PV=nRT

(5.4)(120)=(4)(0.0821)T

648=(0.3284)T

1973. = T

Using the ideal gas equation, T is measured in Kelvin.

Or, you could isolate T:

T = PV/nR

The answer is the same.

3 0
3 years ago
How does the angular diameter of an object change as you move away from the object?
7nadin3 [17]

Explanation :

Angular diameter of a sphere or a circle shows how large a sphere or a circle appears from a given point. It is the angle between the initial and final positions.

The angular diameter of a given sphere or a circle is given by :

             \delta =2arc\ tan\dfrac{d}{2D}

where \delta is angular displacement

d is actual diameter of object

D is distance to the center of sphere

So, angular displacement is inversely proportional to the distance from the object.

<em>Hence, as we move away from the object the angular diameter of an object gets smaller.</em>

5 0
3 years ago
Read 2 more answers
A "home-made" solid propellant rocket has an initial mass of 9 kg; 6.8 kg of this is fuel. The rocket is directed vertically upw
nlexa [21]

Answer:

v = 1176.23 m/s

y = 741192.997 m = 741.19 km

Explanation:

Given

M₀ = 9 Kg  (Initial mass)

me = 0.225 Kg/s   (Rate of fuel consumption)

ve = 1980 m/s    (Exhaust velocity relative to rocket, leaving at atmospheric pressure)

v = ? if t = 20 s

y = ?

We use the equation

v = ∫((ve*me)/(M₀ - me*t)) dt - ∫g dt     where t ∈ (0, t)

⇒   v = - ve*Ln ((M₀ - me*t)/M₀) - g*t

then we have

v = - 1980 m/s*Ln ((9 Kg - 0.225 Kg/s*20 s)/(9 Kg)) - (9.81 m/s²)(20 s)

v = 1176.23 m/s

then we apply the formula

y = ∫v dt = ∫(- ve*Ln ((M₀ - me*t)/M₀) - g*t) dt

⇒   y = - ve* ∫ Ln ((M₀ - me*t)/M₀) dt - g*∫t dt

⇒   y = - ve*(Ln((M₀ - me*t)/M₀)*t + (M₀/me)*(M₀  - me*t - M₀*Ln(M₀ - me*t))) - (g*t²/2)

For t = 20 s   we have

y = Ln((9 Kg - 0.225 Kg/s*20 s)/9 Kg)*(20 s) + (9 Kg/0.225 Kg/s)*(9 Kg  - 0.225 Kg/s*20 s - 9 Kg*Ln(9 Kg - 0.225 Kg/s*20 s)) - (9.81 m/s²*(20 s)²/2)

⇒   y = 741192.997 m = 741.19 km

The graphs are shown in the pics.

6 0
3 years ago
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