Answer: a = 1.32m/s2
Therefore, the average acceleration is 1.32m/s2
Explanation:
Acceleration is the rate of change in the velocity per time
a = change in velocity/time
a = ∆v/t
average acceleration a = (v2 -v1)/t. ....1
Given;
Final velocity v2 = 1.63m/s
Initial velocity v1 = -1.15ms
time taken t = 2.11s
Substituting into eqn 1
a = [1.63 - (-1.15)]/2.11
a = (1.63+1.15)/2.11
a = 2.78/2.11
a = 1.32m/s2
Therefore, the average acceleration is 1.32m/s2
Habitat
-In the Sonoran Desert region, elf owls are found mainly in riparian habitats (places where there is water), or in areas where saguaro cactus are plentiful.
Range
-Elf Owls are found from the southwest USA to Central Mexico and Baja California. Northern populations winter in Central Mexico and on the Pacific slope north to Sinaloa, Mexico.
Wild Status
-The most important threat to the elf owl is habitat loss both of its riparian forest habitat and desert-scrub habitats. In Arizona, the elf owl is not uncommon, but it's numbers are decreasing in California and Texas.
-So I mean like ya it's possible that they could live in cacti. Sorry that I couldn't give you a straight answer.
couldlive in
Part 1. F= m*a
M=12kg
A= 3 m/s^2
So F = 12kg * 3 m/s^2 which means
F=36 Newton’s
Part 2. F=12000N
M= F/A
A=4 m/s^2
So M= 12000N / 4 m/s^2
Which means M=3000 kg
The acceleration of the car,
![a = \frac{v-u}{t}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7Bv-u%7D%7Bt%7D)
Here, v is final velocity, u is initial velocity and t is time taken by the car.
Given
,
and ![t = 3.0 s = 3.0 \times \frac{1 \ h}{3600} = 8.3 \times 10^{-4} h](https://tex.z-dn.net/?f=t%20%3D%203.0%20s%20%3D%203.0%20%5Ctimes%20%5Cfrac%7B1%20%5C%20h%7D%7B3600%7D%20%3D%208.3%20%5Ctimes%2010%5E%7B-4%7D%20h)
Therefore, from above equation
.
Here, negative sign shows deceleration of a car.
Thus the the magnitude of car acceleration is
.
With the exception of Asthma, all of those things, and a lot more that you don't want, could result from untreated diabetes.