1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olga_2 [115]
2 years ago
11

A 10 ohms resistor is powered by a 5-V battery. The current flowing through the source is:

Physics
1 answer:
mario62 [17]2 years ago
4 0
  • Resistance=R=10ohm
  • Voltage=V=5V
  • Current=I

Applying ohm's law

\\ \sf\longmapsto \dfrac{V}{I}=R

\\ \sf\longmapsto I=\dfrac{V}{R}

\\ \sf\longmapsto I=\dfrac{5}{10}

\\ \sf\longmapsto I=0.5A

You might be interested in
When a puddle of water evaporates, does the water change into a new kind of matter
PIT_PIT [208]
Evaporated water changes form into gas
8 0
3 years ago
When low on gasoline, is it better to increase or decrease the speed of the vehicle? Explain.
sergiy2304 [10]
Yeah!! It is better to decrease the speed of the vehicle so the ejection of gases would happen in slow manner.... then you can save your gasoline
5 0
3 years ago
The Moon and Earth rotate about their common center of mass, which is located about RcM 4700 km from the center of Earth. (This
erica [24]

To solve this problem it is necessary to apply the concepts related to gravity as an expression of a celestial body, as well as the use of concepts such as centripetal acceleration, angular velocity and period.

PART A) The expression to find the acceleration of the earth due to the gravity of another celestial body as the Moon is given by the equation

g = \frac{GM}{(d-R_{CM})^2}

Where,

G = Gravitational Universal Constant

d = Distance

M = Mass

R_{CM} = Radius earth center of mass

PART B) Using the same expression previously defined we can find the acceleration of the moon on the earth like this,

g = \frac{GM}{(d-R_{CM})^2}

g = \frac{(6.67*10^{-11})(7.35*10^{22})}{(3.84*10^8-4700*10^3)^2}

g = 3.4*10^{-5}m/s^2

PART C) Centripetal acceleration can be found throughout the period and angular velocity, that is

\omega = \frac{2\pi}{T}

At the same time we have that centripetal acceleration is given as

a_c = \omega^2 r

Replacing

a_c = (\frac{2\pi}{T})^2 r

a_c = (\frac{2\pi}{26.3d(\frac{86400s}{1days})})^2 (4700*10^3m)

a_c = 3.34*10^{-5}m/s^2

3 0
3 years ago
How much does 1 liter of water weigh
Zinaida [17]

Weight = (mass) x (gravity)

On Earth ...

Weight = (1 kg) x (9.8 m/s^2)

Weight = 9.8 Newtons

8 0
3 years ago
How many hydrogen atoms are there in the following compound: 4CHA (2 points)
pogonyaev

Answer:

answer a, 4

Explanation:

when the 4 is before the compound it applies to the whole compound

6 0
3 years ago
Read 2 more answers
Other questions:
  • A visitor to a lighthouse wishes to determine the height of the tower. She ties a spool of thread to a small rock to make a simp
    7·1 answer
  • Which of the following describes what needs to occur to reduce force and to do the same amount of work?
    14·1 answer
  • A 1.0 kg object moving at 4.5 m/s has a wavelength of:
    12·1 answer
  • "Which particle builds a static electric charge when it is transferred from one object to another?
    11·1 answer
  • certification programs are available at all of the following except A. online schools B. vocational school C. community colleges
    8·2 answers
  • If the plane travels at 600 km/h for 2 hours, how far has it traveled?
    15·1 answer
  • Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.360 mm wide. The diffraction pattern is observed
    5·1 answer
  • Now consider a wave which is paired with seven other waves into seven pairs. The two waves in each pairing are identical, except
    10·1 answer
  • This is the equation for the formation of magnesium chloride. Mg(s) + 2HCl(l) → MgCl2(aq) + H2(g) Which are the reactants and th
    13·1 answer
  • What is the voltage across resistor #2? (must include unit - V)
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!