Its most likely C. Remember the bigger the vehicle the bigger the area it needs to make a safe turn.
The energy that the rope absorbs from the climber is Ep=m*g*h where m is mass of the climber, g=9.81m/s² and h is the height the climber fell. h=4 m+2 m because he was falling for 4 meters and the rope stretched for 2 aditional meters. The potential energy stored in the rope is Er=(1/2)*k*x², where k is the spring constant of the rope and x is the distance the rope stretched and it is
x=2 m. So the equation from the law of conservation of energy is:
Ep=Er
m*g*h=(1/2)*k*x²
k=(2*m*g*h)/x² = (2*60*9.81*6)/2² = 7063.2/4 =1765.8 N/m
So the spring constant of the rope is k=1765.8 N/m.
Answer: The torque required is 0.0471 N m.
Explanation:
Mass of the disc = 200 g = 0.2 kg (1 kg =1000 g)
Radius of the disc =
= 10 cm = 0.1 m(1 m = 100 cm)
Angular acceleration = 
Moment of inertia = 
The torque required is 0.0471 N m.
Both objects have the same electrical charge. Opposite charges attract. And if they were neutral they would not do anything.
