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Licemer1 [7]
3 years ago
12

What three structures to the bodies of all vascular plants have?? HELP!!!!

Physics
1 answer:
bearhunter [10]3 years ago
3 0
All vascular plants have parenchyma, collenchym<span>Vascular tissue transports food, water, hormones and minerals within the plant. Vascular tissue includes </span>xylem<span>, </span>phloem<span>, parenchyma, and cambium cells.</span>a, and sclerenchyma cells. Hoped it help!
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A robot arm that controls the position of a video camera in an automated surveillance system is manipulated by a servo motor tha
lesya [120]

Answer:

W = 270.9 J

Explanation:

given,  

F(x) = (12.9 N/m²) x²  

work = Force x displacement  

dW = F  .dx  

the push-rod moves from x₁= 1 m to x₂ = 4 m

integrating the above  

\int dW = \int_{x_1}^{x_2}F. dx

W = \int_{x_1}^{x_2}F. dx

W = \int_{1}^{4} (12.9 x^2) dx

W = 12.9\times [\dfrac{x^3}{3}]_1^4 dx

`W = 12.9\times [\dfrac{4^3}{3}-\dfrac{1^3}{3}] dx

W = 270.9 J

work done by the motor is W = 270.9 J

6 0
3 years ago
Which one please hurry . And please be right ..
Elis [28]

Answer:

IN MOTION

Explanation:

An apparent change in the frequency of waves, as of sound or light, occurring when the source and observer are in motion relative to each other, with the frequency increasing when the source and observer approach each other and decreasing when they move apart.

8 0
3 years ago
Read 2 more answers
A boy sleds down a hill and onto a frictionless ice- covered lake at 10.0 m/s. In the middle of the lake is a 1000-kg boulder. W
mina [271]

Answer:

The speed of the sled is 9.2 m/s

The speed of the boulder is 0.82 m/s

Solution:

As per the question:

Mass of the boulder, m_{B} = 1000\ kg

Mass of the sled, m_{S} = 2.50\ kg

Mass of the boy, m_{b} = 40\ kg

Initial Velocity, v = 10.0 m/s

Now,

To calculate the speed of both the sled and the boulder after the occurrence of the collision:

m = m_{b} + m_{S} = 40 + 2.50 = 42.50\ kg

Initial velocity of the boulder, v_{B} = 0\ m/s

Since, the collision is elastic, both the energy and momentum rem,ain conserved.

Now,

Using the conservation of momentum:

mv + m_{B}v_{B} = mv' + m_{B}v'_{B}

where

v' = final velocity of the the system of boy and sled

v'_{B} = final velocity of the boulder

42.50\times 10 + m_{B}.0 = 42.50v' + 1000v'_{B}

42.50v' + 1000v'_{B} = 425            (1)

Now,

Using conservation of energy:

\frac{1}{2}mv^{2} + \frac{1}{2}m_{B}v_{B}^{2} = \frac{1}{2}mv'^{2} + \frac{1}{2}m_{B}v'_{B}^{2}

42.50\times 10^{2} + m_{B}.0 = 42.50v'^{2} + 1000v'_{B}^{2}

42.50v'^{2} + 1000v'_{B}^{2} = 4250         (2)

Now, from  eqn (1) and (2):

v' = \frac{m - m_{B}}{m + m_{B}}\times v

v' = \frac{42.50 - 1000}{42.5 + 1000}\times 10 = - 9.2\ m/s

Now,

v'_{B} = \frac{2m}{m + m_{B}}\times v

v'_{B} = \frac{2\times 42.50}{42.5 + 1000}\times 10 = 0.82\ m/s

5 0
3 years ago
Read 2 more answers
To see if your results are reasonable, you can compare the final velocity of the stone as it falls down unwinding the wire from
pentagon [3]

Answer:

The velocity of the stone is 2.57 m/s.

Explanation:

Given that

Height = 0.337 m

We need to calculate the velocity of the stone

Using equation of motion

v^2-u^2=2gh

Where, v = velocity of stone

u = initial velocity

g = acceleration due to gravity

h = height

Put the value into the formula

v^2-0=2\times9.8\times 0.337

v=\sqrt{2\times9.8\times0.337}

v=2.57\ m/s

Hence, The velocity of the stone is 2.57 m/s.

7 0
4 years ago
Under specific circumstances, waves will bend around obstacles. This type of bending is called
BartSMP [9]
That type of bending is called "diffraction" of waves.
6 0
3 years ago
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