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3 years ago

What three structures to the bodies of all vascular plants have?? HELP!!!!

1 answer:

3 0

All vascular plants have parenchyma, collenchymVascular tissue transports food, water, hormones and minerals within the plant. Vascular tissue includes xylem, phloem, parenchyma, and cambium cells.a, and sclerenchyma cells. Hoped it help!

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Social learning theory indicates that learning occurs from _____.

poizon [28]

This is psychology and not physics by the way , it occurs from direct instruction or observation

6 0

3 years ago

A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that incre

Evgen [1.6K]

Complete Question

A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 1.60 T in 0.99 s. What is the resulting induced current if the loop has a resistance of $1.20 \ \Omega$

Answer:

The current is $I = 0.0007 41 \ A$

Explanation:

From the question we are told that

The area is $A = 8.00 \ cm^2 = 8.0 *10^{-4} \ m^2$

The initial magnetic field at $t_o = 0 \ seconds$ is $B_i = 0.500 \ T$

The magnetic field at $t_1 = 0.99 \ seconds$ is $B_f = 1.60 \ T$

The resistance is $R = 1.20 \ \Omega$

Generally the induced emf is mathematically represented as

$\epsilon = A * \frac{B_f - B_i }{ t_f - t_o }$

=> $\epsilon = 8.0 *10^{-4} * \frac{1.60 - 0.500 }{ 0.99- 0 }$

=> $\epsilon = 0.000889 \ V$

Generally the current induced is mathematically represented as

$I = \frac{\epsilon}{R }$

=> $I = \frac{0.000889}{ 1.20 }$

=> $I = 0.0007 41 \ A$

6 0

3 years ago

Cesium-137 undergoes beta decay and has a half-life of 30.0 years. How many beta particles are emitted by a 14.0-g sample of ces

Mandarinka [93]

Answer: $0.81\times 10^{16}$ beta particles

Explanation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass = 14.0 g

Molar mass = 137 g/mol

$\text{Number of moles of cesium}=\frac{14.0g}{137g/mol}=0.102moles$

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.