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Licemer1 [7]
3 years ago
12

What three structures to the bodies of all vascular plants have?? HELP!!!!

Physics
1 answer:
bearhunter [10]3 years ago
3 0
All vascular plants have parenchyma, collenchym<span>Vascular tissue transports food, water, hormones and minerals within the plant. Vascular tissue includes </span>xylem<span>, </span>phloem<span>, parenchyma, and cambium cells.</span>a, and sclerenchyma cells. Hoped it help!
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Answer all of these questions and you will get the brainlist
Rina8888 [55]
7) PE= Fwh = (72 m) (966 N) = 69552 Joules 7
8) zero PE=mass*g*height
I hope it’s correct
6 0
3 years ago
PLEASE HELP ME IM ON A TIMER
garri49 [273]

Answer:

Displacement: 6.71 m, Direction: 63.4 degrees north of east

Explanation:

In the attached image we can aprecciate each one of the movements of the parade. Let's say that the parade started from the origin (point (0,0)) then it moves to the east 4 blocks it means now the parade is located at point (4,0).

Then the parade went to the south three blocks, so it moves to the coordinate (4,-3). After this the parade went to the west one block so the new coordinate point is (3, -3).

And finally the movement of the 0 parade was 9 blocks to the north. It means the final point is now (0,9) - (3,-3) = (3,6)

And the displacement will be defined by the folliwing vector operation:

A (0,0) = oi + 0j\\F (3,6) = 3i + 6 j\\Displacement vector = (3-0)i + (6-0)j = 3i + 6j

We know that the magnitude of the displacement vector is defined by the phytagoras theorem

Displacement = \sqrt{(3)^2+ (6)^2} \\Displacement = 6.70

And the angle will be defined by:

tan(beta)=3/6

beta = tan^-1(6/3)

beta = 63.43°

5 0
3 years ago
A high speed train travels with an average speed of 227 km/h. The train travels for 2 h.how far does the train travel in meters?
Sedbober [7]

2 x 227 km/h = 454 m

8 0
3 years ago
Read 2 more answers
A child dangles a 1.50-kilogram stuffed toy 0.500 meters from the ground. What is the potential energy of the toy?
inn [45]
Since we know that
Gravitational potential energy = mass × height ×gravity

then

GPE = 1.5 kg x 0.500 m x 9.8m/s^2

therefore

GPE = 7.35 J
6 0
3 years ago
Read 2 more answers
How long with it take an object to accelerate from 6 m/s to 13 m/s at a rate of 1.4<br> m/s2. *
Blizzard [7]

Explanation:

hello,

a = ( v - u ) / t

where u is the initial velocity.

and v is the final velocity.

t represents time,

and a represents acceleration.

in this case,

a = 1.4 m/s²

u = 6 m/s

v = 13 m/s

hence,

1.4 = (13 - 6)/t

1.4t = 7

t = 7/1.4

t = 5 s

thank you!

7 0
2 years ago
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