Answer: 2.1 × 10^7 m/s
Explanation:
Please see the attachments below
Beta particles come from the nucleus. Electrons are found around the nucleus.
Beta particles normally travel very fast out of a nucleus in a straight line. Electrons normally orbit the nucleus of an atom.
They both have the same mass and the same charge.
This electric force calculator will enable you to determine the repulsive or attractive force between two static charged particles. Continue reading to get a better understanding of Coulomb's law, the conditions of its validity, and the physical interpretation of the obtained result.
How to use Coulomb's law
Coulomb's law, otherwise known as Coulomb's inverse-square law, describes the electrostatic force acting between two charges. The force acts along the shortest line that joins the charges. It is repulsive if both charges have the same sign and attractive if they have opposite signs.
Coulomb's law is formulated as follows:
F = keq₁q₂/r²
where:
F is the electrostatic force between charges (in Newtons),
q₁ is the magnitude of the first charge (in Coulombs),
q₂ is the magnitude of the second charge (in Coulombs),
r is the shortest distance between the charges (in m),
ke is the Coulomb's constant. It is equal to 8.98755 × 10⁹ N·m²/C². This value is already embedded in the calculator - you don't have to remember it :)
Simply input any three values
<span>The component most affected by the collisions is vertical. The ball's vertical will either decrease or increase due to the collision. If the velocity is high during the collsion the ball's vertical will likely be higher and if the ball's velocity is low the vertical will be as well.</span>
PART a)
here when stone is dropped there is only gravitational force on it
so its acceleration is only due to gravity
so we will have

Part b)
Now from kinematics equation we will have

now we have
y = 25 m
so from above equation


Part c)
If we throw the rock horizontally by speed 20 m/s
then in this case there is no change in the vertical velocity
so it will take same time to reach the water surface as it took initially
So t = 2.26 s
Part D)
Initial speed = 20 m/s
angle of projection = 65 degree
now we have




PART E)
when stone will reach to maximum height then we know that its final speed in y direction becomes zero
so here we can use kinematics in Y direction



so it will take 1.85 s to reach the top