Gravity
Explanation:
Johanna's table:
Circular motion Centripetal force
space station in orbit X
a child in a swing
a ball on a string
The type of centripetal force at work in a space station in orbit is the force of gravity.
The force of gravity is constantly pulling and attractive all objects and bodies to its center.
This force is directed towards the center of the orbit of the earth and it is a centripetal force
- Gravity attracts any object that has mass.
- The mass of the satellite and the earth keeps it in orbit and prevents it from moving out of orbit.
- The more the mass the more the gravitational attraction.
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Answer:
≈ 473 J
Explanation:
m ( mass ) = 2.5 kg
T ( tension ) = 12 N
v = constant
h ( height ) = 6.31 m
d ( diameter ) = 52.3 m
<u>Determine how much thermal energy is created </u>
considering that external force acts on the system
ΔE = W and this can be rewritten as
mgh + ΔEth = W --------- ( 1 )
where ΔEth = amount of thermal energy created
also ; W = Fd cos ∅, hence Work done by Tension force (w) = Td cos 0 = Td
back to equation ( 1 )
mgh + ΔEth = Td
ΔEth = Td - mgh
= ( 12 * 52.3 ) - ( 2.5 * 9.8 * 6.31 )
≈ 473 J
Work done by a body to the system is the product of the force applied and the distance to which the system moved. The distance must be in the same direction as the force. In the given above, the force applied is 30 N and the distance is 5 meters. Multiplying the two gives an answer of 150 Nm. Hence, the answer is 150 joules.
Because when you open the faucet, you want the water to
rush out with pressure, not just dribble or ooze out. The
water has to be supplied to the user with pressure. Either
you supply it from a height, or else you'll need to use pumps
to make the pressure.
Answer:
F = 1.0178 × 10^(-2) dyne
Explanation:
From stokes law, the viscous force also known as drag force on rain drop is given by the formula;
F = 6πηrv
Where;
η is viscosity
r is radius
v is velocity
We are given;
η = 18 × 10^(-5) poise
r = 0.3 mm = 0.03 cm
v = 1 m/s = 100 cm/s
Thus;
F = 6π × 18 × 10^(-5) × 0.03 × 100
F = 1.0178 × 10^(-2) dyne