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Sladkaya [172]
4 years ago
5

What orientation of velocity and acceleration will cause something to initially slow down

Physics
1 answer:
SashulF [63]4 years ago
3 0
Acceleration and velocity in opposite directions
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8 0
3 years ago
5. If x = 0.6 and y = 5, the value of 2(xy)^3 is...
taurus [48]

Explanation:

=2(0.6 * 5)³

=2( 3 )³

=2(27)

=54

3 0
3 years ago
Read 2 more answers
Emily holds a banana of mass m over the edge of a bridge of height h. She drops the banana and it falls to the river below. Use
Sladkaya [172]

Answer:

The speed of the banana just before it hits the water is:

√(2 · g · h) = v

Explanation:

Hi there!

Before Emily throws the banana, its potential energy is:

PE = m · g · h

Where:

PE = potential energy.

m = mass of the banana.

g = acceleration of the banana due to gravity.

h = height of the bridge (distance from the bridge to the ground).

When the banana reaches the water, all its potential energy will have converted to kinetic energy. The equation for kinetic energy is as follows:

KE = 1/2 · m · v²

Where:

KE = kinetic energy.

m = mass of the banana.

v = speed.

Then, when the banana hits the water:

m · g · h = 1/2 · m · v²

multiply by 2 and divide by m both sides of the equation:

2 · g · h = v²

√(2 · g · h) = v

5 0
4 years ago
A sample contains radioactive atoms of two types, A and B. Initially there are five times as many A atoms as there are B atoms.
victus00 [196]

Answer:

Explanation:

Initially no of atoms of A = N₀(A)

Initially no of atoms of B = N₀(B)

5 X N₀(A)  = N₀(B)

N = N₀ e^{-\lambda t}

N is no of atoms after time t , λ is decay constant and t is time .

For A

N(A) = N(A)₀ e^{-\lambda_1 t}

For B

N(B) = N(B)₀ e^{-\lambda_2 t}

N(A) = N(B) , for t = 2 h

N(A)₀ e^{-\lambda_1 t} = N(B)₀ e^{-\lambda_2 t}

N(A)₀ e^{-\lambda_1 t} = 5 x N₀(A)  e^{-\lambda_2 t}

e^{-\lambda_1 t} = 5  e^{-\lambda_2 t}

e^{\lambda_2 t} = 5  e^{\lambda_1 t}

half life = .693 / λ

For A

.77 =  .693 / λ₁

λ₁ = .9 h⁻¹

e^{\lambda_2 t} = 5  e^{\lambda_1 t}

Putting t = 2 h , λ₁ = .9 h⁻¹

e^{\lambda_2\times  2} = 5  e^{.9\times  2}

e^{\lambda_2\times  2} = 30.25

2 x λ₂ = 3.41

λ₂ = 1.7047

Half life of B = .693 / 1.7047

= .4065 hours .

= .41 hours .

6 0
3 years ago
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