Wavelength is the distance between identical points in the adjacent cycles of a waveform signal propagated in space or along a wire. In wireless systems, this length is usually specified in meters, centimeters, or millimeters.
Wavelengths are an important factor in Wi-Fi networks. Wi-Fi operates at five frequencies, all in the gigahertz range: 2.4 GHz, 3.6 GHz, 4.9 GHz, 5 GHz and 5.9 GHz. Higher frequencies have shorter wavelengths, and signals with shorter wavelengths have more trouble penetrating obstacles like walls and floors.
As a result, wireless access points that operate at higher frequencies with shorter wavelengths, often consume more power to transmit data at similar speeds and distances achieved by devices that operate at lower frequencies, with longer wavelengths.
Physics is the branch of science that deals with the structure of matter and how the fundamental constituents of the universe interact. It studies objects ranging from the very small using quantum mechanics to the entire universe using general relativity.
Answer:
The speed of the banana just before it hits the water is:
√(2 · g · h) = v
Explanation:
Hi there!
Before Emily throws the banana, its potential energy is:
PE = m · g · h
Where:
PE = potential energy.
m = mass of the banana.
g = acceleration of the banana due to gravity.
h = height of the bridge (distance from the bridge to the ground).
When the banana reaches the water, all its potential energy will have converted to kinetic energy. The equation for kinetic energy is as follows:
KE = 1/2 · m · v²
Where:
KE = kinetic energy.
m = mass of the banana.
v = speed.
Then, when the banana hits the water:
m · g · h = 1/2 · m · v²
multiply by 2 and divide by m both sides of the equation:
2 · g · h = v²
√(2 · g · h) = v
Answer:
Explanation:
Initially no of atoms of A = N₀(A)
Initially no of atoms of B = N₀(B)
5 X N₀(A) = N₀(B)
N = N₀ 
N is no of atoms after time t , λ is decay constant and t is time .
For A
N(A) = N(A)₀ 
For B
N(B) = N(B)₀ 
N(A) = N(B) , for t = 2 h
N(A)₀ = N(B)₀
N(A)₀ = 5 x N₀(A)
= 5
= 5 
half life = .693 / λ
For A
.77 = .693 / λ₁
λ₁ = .9 h⁻¹
= 5
Putting t = 2 h , λ₁ = .9 h⁻¹
= 5 
= 30.25
2 x λ₂ = 3.41
λ₂ = 1.7047
Half life of B = .693 / 1.7047
= .4065 hours .
= .41 hours .
